The length of the DEFG rectangle
is 6/4 of the length of the ABCD rectangle.
6/4=3/2 = 1,5
How many times greater than the surface of ABCD is the DEFG area?
1,5 times
18%, because 50 - 100, meaning 1 is 2% so 9x2 is 18
The subset of A is B = {1, 2} and the proper subset of A is C = {1,2,3,4}
<h3>How to create the Subset and Proper Subset of the set?</h3>
The set is given as:
A = {1,2,3,4}
Subsets of a set are sets that can be found in another set
An instance of this is
B = {1, 2}
Because all the elements of set B are in set A
Proper subsets of a set are sets that contain the exact elements found in another set
An instance of this is
C = {1,2,3,4}
Because set C and set A have the same elements
Read more about subsets at:
brainly.com/question/6948738
#SPJ1
Answer:
probability that student passes = 0.7815
Step-by-step explanation:
Given:
Student studies = 85% = 0.85
Student not study = 11% = 0.11
Student who pass = 90% = 0.90
Computation:
P(student not pass) = 1 - 0.85
P(student not pass) = 0.15
probability that student passes = P(Student studies)(Student who pass) + P(Student not study)(student not pass)
probability that student passes = (0.85)(0.90) + (0.15)(0.11)
probability that student passes = 0.765 + 0.0165
probability that student passes = 0.7815
This is most easily done using the expanded form of the expression.
∫(9 -9t +t² -t³)dt = 9t -(9/2)t² +(1/3)t³ -(1/4)t⁴ +c
