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3 years ago

13

What information is needed to determine that the two triangles are congruent be ASA?

2 answers:

gladu [14]3 years ago

6 0

9514 1404 393

Answer:

see below

Step-by-step explanation:

ASA requires two angles and the side that lies between them. The list below is a list of such. (The ends of the segments are the vertices of the angles.)

Anna007 [38]3 years ago

5 0

Answer:

ASA: If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent. SAS: If any two angles and the included side are the same in both triangles, then the triangles are congruent.

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The black figure is an ellipse, and the black line segment is its major axis. What is the length of the blue line segment?

andrezito [222]

The answer is: A. 20.3

The explanation is shown below:

1. By definition, the sum of the length of the strings (The length of the blue segment and the length of the red segment) is equal to the length of the major axis (The black segment).

2. Based on this, you can write the following expression, where $x$ is the length of the blue segment:

$x+10.7=31$

3. Now, you must solve for $x$ , as following:

$x=31-10.7$

$x=20.3$

4. Therefore, the answer is the option A.

6 0

4 years ago

What is the property of 96+13=13+96?

Basile [38]

Communitive property

5 0

3 years ago

Find the value of x.

VikaD [51]

Answer:

X = 9

okay If I'm wrong sry what's 9x3 it's 45 right ( me not using a caluctalter ) ( I didn't even spell that Right lol ) but anyways it's X=9

4 0

3 years ago

What is the expression for the below sequence (use n)<br><br> -3,-6,-9,-12

polet [3.4K]

Answer:

$a_{n}$ = - 3n

Step-by-step explanation:

There is a common difference between consecutive terms, that is

- 6 - (- 3) = - 9 - (- 6) = - 12 - (- 9) = - 3

This indicate the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3 and d = - 3 , thus

$a_{n}$ = - 3 - 3(n - 1) = - 3 - 3n + 3 = - 3n

The n th term is - 3n

6 0

4 years ago

g The fencing of the left border costs $10 per foot, while the fencing of the lower border costs $2 per foot. (No fencing is req

klio [65]

Answer:

$Area = 1690ft^2\\x = 130ft, y = 26ft$

Step-by-step explanation:

Given the costs we can form an equation:

$10y + 2x =520 - Eq(A)$

and fencing is triangular such that the area enclosed can be written as:

$A = \dfrac{xy}{2} -Eq(B)$

First need to convert the above equation so that it is only in terms of one variable. [either x or y]

To make the equation only in terms of $x$ we can substitute $y$ from Eq(A) i.e, $y =\frac{520-2x}{10}$ , to Eq(B)

$A = \dfrac{x}{2} \dfrac{520-2x}{10}$

simplify

$A = \dfrac{520x - 2x^2}{20}$

$A = -\dfrac{1}{10}x^2 + 26x$

Now, in order to find the maximum area enclosed we can find $\frac{dA}{dx}$ and equate it zero.

$\dfrac{dA}{dx} = -\dfrac{1}{5}x + 26$

$0 = -\dfrac{1}{5}x + 26$

$-26 = -\dfrac{1}{5}x$

$x = 130$

we have the length of one dimension: specifically, the lower fence will be $x =130ft$

we can use this value of $x$ to find the corresponding value of $y$ . From Eq(A)

$10y + 2x =520$

$10y +2(130) = 520$

$y = \dfrac{520 - 2(130)}{10}$

$y = 26$

the length of the left fence will be $y =26ft$

The enclosed area by the fence will be

$A = \dfrac{xy}{2}$

$A = \dfrac{(130)(26)}{2}$

$A = 1690$

Hence the maximum area that can enclosed by the fences provided the costs will be $1690ft^2$

You can even check the cost of the dimensions whether they all add up to $520 or not.

Use Eq(A)

$10y + 2x =520$

$10(26) + 2(130) =520$

and indeed it does!

5 0

3 years ago