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motikmotik
3 years ago
10

There are 96 dogs at the dog park.

Mathematics
2 answers:
BARSIC [14]3 years ago
6 0

Answer:

4 dogs :]

Step-by-step explanation:

1/8 brown dogs = 12 dogs

5/6 black dogs = 80 dogs

12 + 80 = 92

96 - 92 = 4

Therefore, 4 dogs are mixed colors.

Hope this helps, sorry if this is wrong! Have a great day! <)

laila [671]3 years ago
3 0

Answer:

4 dogs.

Step-by-step explanation:

To solve this, we can find 1/8 of the dogs and 5/6 of the dogs then add them together. (This is the total amount of brown and black dogs.) Then, we can subtract this number from 96 (total) to find the rest (mixed colors).

1/8 of 96 is 12. There are 12 brown dogs.

5/6 of 96= 96/6*5= 80. There are 80 black dogs.

80+12=92.

Subtract that from 96 and you get 4—the number of dogs with mixed colors.

4 dogs are mixed colors.

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i thank it is 25 seconds.  

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3 0
3 years ago
I need help with this
larisa [96]

Answer:

Not similar

Step-by-step explanation:

Even though

8/2=16/4,

10/3 does not have any relation to the rest. Still make sure if im right, but hope this helps!

6 0
3 years ago
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vichka [17]

112 m³

the solid is a rectangular pyramid with volume (V)

V = \frac{1}{3} × area of base × height = \frac{1}{3} × (8 × 4.2 ) × 10 = 112 m³



4 0
3 years ago
What is the arc length of an arc with radius 15 inches and central angle 30 degrees
RUDIKE [14]

Answer:

7.855 inches

Step-by-step explanation:

The formula to find the length of an arc is :

Arc Length = \frac{\theta}{360} × 2 π r

Here,

Θ ⇒ size of the angle ⇒ 30°

r ⇒ radius ⇒ 15 inches

<u>Let us solve it now.</u>

Arc length = \frac{\theta}{360} × 2 π r

Arc length = \frac{30}{360}*2*\pi*15

Arc length = \frac{30*2*\pi*15}{360}

Arc length = \frac{2827.8}{360}

Arc length = 7.855 inches

Let me know if you have any other questions. :)

7 0
2 years ago
PLSS HELP ILL GIVE YOU BRAINLIEST!!
uysha [10]

Answer:

Step-by-step explanation:

Q1)

Use Phythogoras theorem:

(AC)^2=(BC)^2+(AB)^2\\BC^2=AC^2-AB^2\\BC^2=6^2-4^2\\BC^2=36-16\\BC^2=20\\\\Apply\ square\ on\ both\ sides\\\\\sqrt{BC^2}=\sqrt{20}  \\BC=\sqrt{20} \\BC=\sqrt{10(2)} \\BC=\sqrt{5(2)(2)} \\BC=2\sqrt{5}

Q2)

Apply phythogoras theorem:

CD^2=CE^2+DE^2\\CD^2=7^2+9^2\\CD^2=49+81\\CD^2=130\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{CD^2} = \sqrt{130} \\\\CD=\sqrt{130} \\\\CD=11.4

Q3)

Apply phythogoras theorem again:

BC^2=BD^2+CD^2\\BC^2=7^2+13^2\\BC^2=49+169\\BC^2=218\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{BC^2} =\sqrt{218}  \\\\BC=\sqrt{218} \\\\BC=14.76

I have an attached an image for Question 2 for better understanding the length of DE in question equals 15 - 6 = 9

4 0
3 years ago
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