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S_A_V [24]
3 years ago
12

How many terms this mathematical expression have? 2x^3-x^4+3-3x^2+3x please help asap

Mathematics
1 answer:
laila [671]3 years ago
7 0
Answer: 5 Explanation- 1: 2x^3; 2: -x^4; 3: 3; 4: -3x^2; 5: 3x
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A survey of 50 people found that 14 people like building a snowman. If 600 people had responded, how many would have been expect
Nimfa-mama [501]

Answer:

168, a little of both

Step-by-step explanation:

Make 14 out of 50, 14/50 simplified its 7/25, multiply it by 600 and you get 168 its a little of both because half the info we were given its experimental since it is not theorized, what we're being given (the question) and what we gave is theorized since we didn't actually perform an experiment to get a real answer

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On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and
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Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

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Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

WX = \sqrt{13}

XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

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How does moving the place of a digit change its value
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In a system of numbers to any other base, moving the place of a digit changes
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