3 years ago

Solve for xa.81b.41c.1681

1 answer:

5 0

A=9 , b=40

Pythagorean theorem
$a^2+b^2=x^2 \\\\ x=\sqrt{a^2+b^2}=\sqrt{9^2+40^2}=\sqrt{81+1600}=\sqrt{1681}=\sqrt{41^2}=41$

You might be interested in

The diagram shows a right angled triangle.

uysha [10]

Answer:

6 root 2

Step-by-step explanation:

Pythagous Therom

A^2 = B^2 + C^2

B^2 = C^2 - A^2

B^2 = 36 - (2 Root 3)^2

B^2 = 24

B = 2 root 6

Base x Height / 2 for area of Triangle

2 root 3 x root 24 = 12 root 2

12 root 2 / 2 = 6 root 2

4 0

2 years ago

Indicate the degree of the term.<br> a^10

icang [17]

Letter “A” to the tenth power

7 0

2 years ago

A jacket is advertised to be 85% off the original price. If the sale price is $102 what is the original price ?

Jobisdone [24]

The answer would prob around $188.70 because .85x102=86.7 so add that to 102 and u get 188.70 but I'm prob wrong and I have a test on this tomorrow

<span />

4 0

2 years ago

What quadratic formula do I need to use to solve 3x(x+6)=-1

timofeeve [1]

Answer:

$\Large \boxed{x_1=\frac{9+\sqrt{51} }{3} \ \ ; \ \ x_2=\frac{9-\sqrt{51} }{3} }$

Step-by-step explanation:

$\displaystyle \Large \boldsymbol{} 3x(x+6)=-10 \\\\3x^2+18x=-10 \\\\3x^2+18x+10=0 \\\\D=324-120=204 \\\\ x_{1;2}=\frac{18\pm2\sqrt{51} }{6} =\frac{9\pm\sqrt{51} }{3}$

3 0

2 years ago

HELPPPPPPPP will give the brainliest pls help

baherus [9]

Answer:

Step-by-step explanation:

i guessed

8 0

2 years ago