Question

Solve for xa.81b.41c.1681

Answer 1

A=9 , b=40

Pythagorean theorem
$a^2+b^2=x^2 \\\\ x=\sqrt{a^2+b^2}=\sqrt{9^2+40^2}=\sqrt{81+1600}=\sqrt{1681}=\sqrt{41^2}=41$