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valentinak56 [21]
3 years ago
11

What is the measure of angle w°? Show all work.

Mathematics
1 answer:
Korolek [52]3 years ago
3 0
It’s 100 I’m pretty sure
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Aaron borrows 150.00 from Austin.he promised to pay back the money in 4 monthly installments.each month he wants to pay half the
elena55 [62]

Answer:

he would want to pay 80

Step-by-step explanation:

if you think about it he wants to pay half of the amount he paid for last month so its basically a trial and error/ guess and check question so i started with 15 and went 15+30 because half of 30 is 15 so you would multiply by 2 so 15+30= 45+60, 60 being half of 30 45+60= 105+120, again half is 60 105+120= 225 once i found out 15 was not correct i then tried the number 10. 10+20= 30+40=70+80= 150

i hope this helps you

8 0
4 years ago
What is the ratio equivalent to 7:2
aleksandrvk [35]
4:14 , 6:21, 8:28, 10:35!!!
6 0
3 years ago
Read 2 more answers
The sum of two numbers is -7. Five times the first number plus the second number is 1. What are the numbers?
arlik [135]

Answer:

Step-by-step explanation:

Well you only want the two equations so here they are.

x + y = -7

5*x + y = 1

I should give you the answer.

x = 2

y = -9 I think. These answers were done in my head.

4 0
3 years ago
Number 2 rewrite as a single power
Paul [167]

Answer:

-625

Step-by-step explanation:

I think so..

4 0
3 years ago
Choose the linear inequality that describes the graph. The gray area represents the shaded region.
jek_recluse [69]

Answer:

2x + 3y ≥ 5

Step-by-step explanation:

See the graph attached.

The bold straight line passes through the points (1,1) and (4,-1).

Therefore, the equation of the straight line will be  

\frac{y + 1}{- 1 - 1} = \frac{x - 4}{4 - 1}

⇒ 3(y + 1) = - 2(x - 4)

⇒ 3y + 3 = - 2x + 8

⇒ 2x + 3y = 5 ............. (1)

Now, the shaded region i.e. the solution to the inequality does not include the origin(0,0).

So, putting x = 0 and y = 0 in the equation (1) we get, 0 < 5

Therefore, the inequality equation is 2x + 3y ≥ 5 (Answer)

6 0
3 years ago
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