Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Answer:
maybe like 5k
Step-by-step explanation:
Answer:
9316000000000
Simply move the decimal 12 places to the left.
If this helped please mark as brainiest <3
Answer:
See the image for solution.
Brainlist please
-5x-10=10 x= -4
Work:
-5x-10=10
+10 +10
______________
-5x=20
_______
-5 -5
x=-4
