Answer:
2 hours
Step-by-step explanation:
Given the following :
Darryl :
Speed = 25mph
Jacob:
Traveled in opposite direction
Speed = 35mph
After Darryl had traveled for 4 hours, Distance between them was 170 miles
Distance traveled by Darryl :
Speed * time = (25 * 4) = 100 miles
Total distance = distance traveled by Darryl + distance traveled by Jacob
170 miles = 100 miles + distance traveled by jacob
Distance traveled by Jacob = 170 - 100
Distance traveled by Jacob = 70 miles
Time = distance / speed
Time traveled by Jacob = 70 miles / 35mph
Time traveled by Jacob = 2 hours
Well, on every test I have at a school and I believe most schools do this. You need at leasr 80% to pass. But to pass you'd most likely need 80% or 70%. But if you get an 80% you'll be sure to pass! I hope this helps you!
Answer:
The enrollment after 5 years is 10,724
Step-by-step explanation:
Generally, we can have the depreciation formula written as follows;
A = P(1 - r)^t
A is the number of enrollment in after a certain number of years t
P is the initial population which is 13,500
r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045
t = 5 years
Substituting these values, we have it that;
A = 13,500(1-0.045)^5
A = 10,723.84
4. SOLVE FOR X:
Using the Alternate Interior Angles Theorem, we know that the 67 degree angle is congruent with the (12x - 5) degree angle. With this information, all I have to do is set the two equal to each other and solve for x.
67 = 12x - 5
67 + 5 = 12x - 5 + 5
72/12 = 12x/12
6 = x
x = 6
SOLVE FOR Y:
Using the Vertical Angles theorem, we know that angle y must be congruent to the 67 degree angle.
y = 67 degrees.
5. SOLVE FOR Y:
Alternate exterior angles: 6(x - 12) = 120
6x - 72 + 72 = 120 + 72
6x/6 = 192/6
x = 32
SOLVE FOR Y:
6((32) - 12) + y = 180
192 - 72 + y = 180
120 + y - 120 = 180 - 120
y = 60
Answer:
yes, triangle DEF is similar to triangle DBC, BC corresponds to EF, and angle DCB corresponds to angle F.
Step-by-step explanation:
Part A: Angle D is congruent to angle D by the reflexive property. Since line BC is parallel to line EF then angle DCB = angle DFE by corresponding angles. Hence triangle DEF is similar to triangle DBS by the AA Similarity Postulate.
Part B: BC corresponds to EF because they are in the same order and the triangles listed DEF and DBC
Part C: Angle DCB corresponds to angle F since they are corresponding angles with the two given parallel lines BC and EF.
