Answer:
Step-by-step explanation:
1) (i) HG ≅ ST ; GI ≅ TR ; IH ≅ RS
ΔHGI ≅ ΔSTR by S S S congruent
(ii) ∠H ≅ ∠S ; HG ≅ ST ; ∠G ≅ ∠T
ΔHGI ≅ ΔSTR by A S A -> Angle Side Angle congruent.
3) LM ≅ XY ; MK ≅ YZ ; KL ≅ ZX
ΔLMK ≅ ΔXYZ Side Side Side congruent
∠K ≅ ∠Z ; KL ≅ ZX ; ∠L ≅ ∠X
ΔLMK ≅ ΔXYZ by Angle Side Angle congruent
Answer: Bottom left corner
Angle DEC and Angle DEH
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Explanation:
I recommend opening your favorite paint program, and using different colors to mark on the drawing as I have done below (see attached image). Note how angle DEC is in red and angle DEH is in blue. The two angles are adjacent, meaning they share the same ray (in this case, ray ED) and they form a straight angle.
Because they form a straight angle, or straight line, this means the two angles are supplementary. Supplementary angles always add to 180.
The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
k=-6
k-4=0
k=4
k=-6 or 4
64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7
so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
A positive times a negative will always be negative
9 x -1 = -9
-9, Hope this helps!
