Answer:
B) 42
Step-by-step explanation:
Area =
b h
Area =
x 12 x7
Area = 42
You would have one tenths (1/10) of a chance to get a 4 on the first go. you would have four ninths (4/9) of a chance to get a number less than 5 out of the bag on the second go.
the overall probability would be two forty-fifths (2/45)
<span>10!/5! =10*9*8*7*6=30,240;;
If order is not considered, 10C5 =10!/5!5!=252 </span>
Answer:
A. 0.5
B. 0.32
C. 0.75
Step-by-step explanation:
There are
- 28 students in the Spanish class,
- 26 in the French class,
- 16 in the German class,
- 12 students that are in both Spanish and French,
- 4 that are in both Spanish and German,
- 6 that are in both French and German,
- 2 students taking all 3 classes.
So,
- 2 students taking all 3 classes,
- 6 - 2 = 4 students are in French and German, bu are not in Spanish,
- 4 - 2 = 2 students are in Spanish and German, but are not in French,
- 12 - 2 = 10 students are in Spanish and French but are not in German,
- 16 - 2 - 4 - 2 = 8 students are only in German,
- 26 - 2 - 4 - 10 = 10 students are only in French,
- 28 - 2 - 2 - 10 = 14 students are only in Spanish.
In total, there are
2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.
The classes are open to any of the 100 students in the school, so
100 - 50 = 50 students are not in any of the languages classes.
A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

B. If a student is chosen randomly, the probability that he or she is taking exactly one language class is

C. If 2 students are chosen randomly, the probability that both are not taking any language classes is

So, the probability that at least 1 is taking a language class is

Answer:
1. 15
2. 8
Step-by-step explanation:
The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)
The nth term of a GP is;
Tn = ar^(n-1)
Where;
a = first term
r = common ratio
For the first sequence;
The common ratio r is
r = T3/T2 = 540/90 = 6
r = 6
T2 = ar^(2-1) = ar
T2 = 90 = ar
Substituting the values of r;
90 = a × 6
a = 90/6
a = 15
First term = 15
2. The sam method applies here.
Common ratio r = T3/T2 = 128/32 = 4
r = 4
T2 = ar^(2-1) = ar
T2 = 32 = ar
Substituting the values of r;
32 = a × 4
a = 32/4
a = 8
First term = 8