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Anna71 [15]
3 years ago
11

What is the slope of the line that contains the point (-1,2) and (3,3)

Mathematics
2 answers:
marysya [2.9K]3 years ago
7 0

Answer: 1/4

Step-by-step explanation: slope = (y2-y1)/(x2-x1)

= (3-2)/(3-(-1))

= 1/4

stepan [7]3 years ago
4 0
The slope of that line would be 1/4!!!
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Jeff reads 5/7 of a book in 4 hours. At this rate, how much did he read in 1 hour? Please answer this correctly. Don't put a lin
leonid [27]

Answer:

Jeff read 5/28 of a book in 1 hour.

Step-by-step explanation:

The rate given is 5/7 of a book read in 4 hours.

If the questions asks how much he read in 1 hour, it means the answer needed is a unit rate.

A unit rate is a rate per unit. In this case, a rate per hour.

Let’s find how much Jeff read in 1 hour:

5/7 in 4 hours is the rate given so:

5/7 ÷ 4

= 5/7 x 1/4

= 5/28 (already simplified/final answer)

SO, Jeff read 5/28 of the book in 1 hour.

Brainliest? Hope this helped!

5 0
3 years ago
Fine the value of x in the triangle. Then classify the triangle as acute, right,
Trava [24]

Answer:

x = 88

Step-by-step explanation:

The sum of the angles in a triangle add to 180

47+45 +x = 180

Combine like terms

92+x = 180

Subtract 92 from each side

92+x-92= 180-92

x =88

7 0
3 years ago
What is the value of x
jok3333 [9.3K]

Answer:

60

Step-by-step explanation:

x = (1/2)(172 - 52)

x = (1/2)(120)

x = 60

8 0
3 years ago
On Monday, Elsbeth’s bank account balance was -$16.75. On Tuesday, she deposited a check for $5.72. On Thursday, she deposited $
koban [17]

Answer:

5.72

Step-by-step explanation:

(-16.75 + 16.75) = 0

0 + 5.72= 5.72

Therefore, the answer is 5.72

4 0
3 years ago
A car insurance company has high-risk, medium-risk, and low-risk clients, who have, respectively, probabilities .04, .02, and .0
Paha777 [63]

Answer:

(a) 0.983

(b) 0.353 or 35.3%

(c) 0.604 or 60.4%

Step-by-step explanation:

a) The probability of a random client does not file a claim is equal to the sum of:

1) the probability of a client being high risk and does not file a claim = P(hr)*(1-P(c_hr))

2) the probability of a client being medium risk and does not file a claim = P(mr)*(1-P(c_mr))

and

3) the probability of a client being low risk and does not file a claim = P(lr)*(1-P(c_lr))

P(not claim) = P(hr)*(1-P(c_hr))+P(mr)*(1-P(c_mr))+P(lr)*(1-P(c_lr))

P(not claim) = 0.15*(1-0.04)+0.25*(1-0.02)+0.6*(1-0.01)

P(not claim) = 0.15*0.96+0.25*0.98+0.6*0.99 = 0.983

(b) To know the proportion of claims that come from high risk clients we need to know the total expected claims in every category:

Claims expected by high risk clients = P(c_hr)*P(hr) = 0.04*0.15 = 0.006 claims/client

Claims expected by medium risk clients = P(c_mr)*P(mr) = 0.02*0.25 = 0.005 claims/client

Claims expected by low risk clients = P(c_lr)*P(lr) = 0.01*0.60 = 0.006 claims/client

The proportion of claims done by high risk clients is

Claims by HR clients / Total claims expected = 0.006 / (0.006+0.005+0.006) =  0.006 / 0.017 = 0.3529 or 35,3%

(c)  The probability of being a client of a particular category and who don't file a claim is:

1) High risk: 0.15*(1-0.04) = 0.144

2) Medium risk: 0.25*(1-0.02) =  0.245

3) Low risk: 0.6*(1-0.01) = 0.594

The probability that a random client who didn't file a claim is low- risk can be calculated as:

Probability of being low risk and don't file a claim / Probability of not filing a claim

P(LR&not claim)/P(not claim) = 0.594 / (0.144+0.245+0.594)

P(LR&not claim)/P(not claim) = 0.594 /  0.983 = 0.604 or 60.4%

6 0
3 years ago
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