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3 years ago

A person with a weight of 120 lbs. is standing on a scale. What force is the

Physics

2 answers:

igor_vitrenko [27]3 years ago

8 0

Answer:

The answer is 120lbs

Explanation:

because the scale exerts enough force to equal out to 0 and since the person is putting 120lbs onto the scale it then pushes back enough force to keep them up

MaRussiya [10]3 years ago

6 0

Answer:

the answer is number 2

Explanation:

because the weight of the scale is added

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If you add a small amount of hydrochloric acid to 4 liters of water, you would create a _____ solution.

Harman [31]

Answer:

The answer is D.

Explanation:

An example of a weak base is ammonia. It does not contain hydroxide ions, but it reacts with water to produce ammonium ions and hydroxide ions. The position of equilibrium varies from base to base when a weak base reacts with water. The further to the left it is, the weaker the base.

5 0

3 years ago

A block of mass 12.2 kg is sliding at an initial velocity of 6.65 m/s in the positive x-direction. The surface has a coefficient

valentina_108 [34]

Explanation:

Given that,

Mass of the block, m = 12.2 kg

Initial velocity of the block, u = 6.65 m/s

The coefficient of kinetic friction, $\mu_k=0.253$

(a)The force of kinetic friction is given by :

$f=\mu_k mg$

mg is the normal force

So,

$f=0.253\times 12.2\times 9.8\\\\f=30.24\ N$

(b) Net force acting on the block in the horizontal direction,

f = ma

a is the acceleration of the block

$a=\dfrac{f}{m}\\\\a=\dfrac{30.24}{12.2}\\\\a=2.47\ m/s^2$

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(6.65)^2}{2\times 2.47}\\\\d=-8.95\ m$

Hence, this is the required solution.

3 0

3 years ago

a rugby player passes the ball 5.34 m across the field, where it is caught at the same height as it left his hand. at what angle

MakcuM [25]

Answer:

$31.035^{\circ}$

Explanation:

x = Displacement in x direction = 5.34 m

t = Time taken to travel the displacement

y = Displacement in y direction = 0

u = Initial velocity of ball = 7.7 m/s

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Displacement in x direction is given by

$x=u\cos\theta t\\\Rightarrow t=\dfrac{5.34}{7.7 \cos\theta}$

Displacement in y direction is given by

$y=u\sin\theta t-\dfrac{1}{2}gt^2\\\Rightarrow 0=7.7\sin\theta \dfrac{5.34}{7.7\cos\theta}-\dfrac{1}{2}\times 9.81 (\dfrac{5.34}{7.7\cos\theta})^2\\\Rightarrow 0=7.7\sin\theta-4.905\times \dfrac{5.34}{7.7\cos\theta}\\\Rightarrow 0=7.7^2\sin\theta \cos\theta-4.905\times 5.34\\\Rightarrow 0=7.7^2\dfrac{\sin2\theta}{2}-4.905\times 5.34\\\Rightarrow 0=7.7^2\sin2\theta-4.905\times5.34\times 2\\\Rightarrow \sin2\theta=\dfrac{4.905\times 5.34\times 2}{7.7^2}\\\Rightarrow 2\theta=\sin^{-1}\dfrac{4.905\times 5.34\times 2}{7.7^2}$

$\Rightarrow \theta=\dfrac{62.07}{2}\\\Rightarrow \theta=31.035^{\circ}$

The angle at which the ball was thrown is $31.035^{\circ}$ .

7 0

3 years ago

A 75-turn coil with a diameter of 6.00 cm is placed in a constant, uniform magnetic field of 1.00 T directed perpendicular to th

kolezko [41]

Answer:

The induced emf in the coil at the t = 5s is 6.363 mV

Explanation:

Given;

number of turns = 75

diameter of the coil = 6 cm

magnetic field strength = 1 T

new magnetic field strength = 1.30 T at t = 10.0 s

$Area \ of \ coil = \frac{\pi d^2}{4} = \frac{\pi *0.06^2}{4} = 0.002828 \ m^2$

$E.M.F = \frac{NA* \delta B}{\delta t}$

Between 0 to 5 s, Induced emf is given as;

$E.M.F = \frac{75*0.002828*(B_5-1)}{5}$

Between 5 to 10 s, Induced emf is given as;

$E.M.F = \frac{75*0.002828*(1.3-B_5)}{5}$

Since the field increased at a uniform rate until it reaches 1.30 T at t = 10.0 s, the induced emf will also increase in uniform rate. And equal time interval will generate same increase in field strength.

B₅ -1 = 1.3 - B₅

2B₅ = 2.3

B₅ = 1.15 T

Thus, magnetic field at t = 5 is 1.15 T

$E.M.F = \frac{75*0.002828*(1.3-1.15)}{5} = 6.363 \ mV$

Therefore, the induced emf in the coil at the t = 5s is 6.363 mV

7 0

3 years ago

Why does a magnet get demagnetized when hammered?

ale4655 [162]

Answer:

Answer is on the pic

Explanation:

I hope it's helpful!

4 0

3 years ago