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LuckyWell [14K]

3 years ago

13

Neptune is approximately 4.5 billion kilometers from the sun. What is this distance in AU?

1 answer:

asambeis [7]3 years ago

7 0

Well, one AU is 149,597,870 km. So, we would basically have to divide 4.5 billion km by 149,597,870, right?

4,500,000,000/149,597,870=30.080642 AU.

So, the correct answer would be 30 AU. Hoped this helped!

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solar panels convert light energy from sunlight into electricity energy what material is most likely used in solar panels and wh

klasskru [66]

<span>Solar panels convert light energy from sunlight into electricity energy , Metalloid is most likely used in solar panels The answer is : </span> A metalloid is used because it is a semiconductor and can become more conductive when more light shines on it. Metalloids are shiny,<span> semiconductive and they are brittle.</span>

6 0

3 years ago

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What is the magnitude of your displacement when you follow directions that tell you to walk 225 m in one direction, make a 90° t

Gekata [30.6K]

Start by facing East. Your first displacement is the vector

<em>d</em>₁ = (225 m) <em>i</em>

Turning 90º to the left makes you face North, and walking 350 m in this direction gives the second displacement,

<em>d</em>₂ = (350 m) <em>j</em>

Turning 30º to the right would have you making an angle of 60º North of East, so that walking 125 m gives the third displacement,

<em>d</em>₃ = (125 m) (cos(60º) <em>i</em> + sin(60º) <em>j</em> )

<em>d</em>₃ ≈ (62.5 m) <em>i</em> + (108.25 m) <em>j</em>

The net displacement is

<em>d</em> = <em>d</em>₁ + <em>d</em>₂ + <em>d</em>₃

<em>d</em> ≈ (287.5 m) <em>i</em> + (458.25 m) <em>j</em>

and its magnitude is

|| <em>d</em> || = √[ (287.5 m)² + (458.25 m)² ] ≈ 540.973 m ≈ 541 m

7 0

3 years ago

g A cylinder of mass m is free to slide in a vertical tube. The kinetic friction force between the cylinder and the walls of the

sdas [7]

Answer:

The vertical distance is $d = \frac{2}{k} *[mg + f]$

Explanation:

From the question we are told that

The mass of the cylinder is m

The kinetic frictional force is f

Generally from the work energy theorem

$E = P + W_f$

Here E the the energy of the spring which is increasing and this is mathematically represented as

$E = \frac{1}{2} * k * d^2$

Here k is the spring constant

P is the potential energy of the cylinder which is mathematically represented as

$P = mgd$

And

$W_f$ is the workdone by friction which is mathematically represented as

$W_f = f * d$

So

$\frac{1}{2} * k * d^2 = mgd + f * d$

=> $\frac{1}{2} * k * d^2 = d[mg + f ]$

=> $\frac{1}{2} * k * d = [mg + f ]$

=> $d = \frac{2}{k} *[mg + f]$

5 0

4 years ago

What is the mass if an object moving with a speed of 9m/s and a kinetic energy if 2000 J

stepladder [879]

Solve for mass:

m= 2k/v(squared)

m=2000(2)/9(squared))

m=49.383 kilograms

7 0

3 years ago

if a car has a constant acceleration of 4 m/s^2, starting from rest, how fast is it traveling after 5 seconds?

UkoKoshka [18]

Answer:

20 m/s

Explanation:

Recall that one of the equations of motions can be written:

v = u + at, (also see attached for reference)

Where,

v = final speed (we are asked to find this)

u = initial speed = 0 (because it starts from rest)

t = time taken = 5s

We simply substitute the given values into the equation:

v = u + at

v = 0 + (4)(5)

v = 20 m/s

3 0

3 years ago

Read 2 more answers