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kipiarov [429]
3 years ago
11

Why does the liquid rise up through the dip tube when the valve is open

Physics
2 answers:
Aleonysh [2.5K]3 years ago
6 0

The liquid rise up through the dip tube when the valve is opened. The propellant gas wants to expand as much as it can, so if the valve is open, the propellant expands and pushes the spray up out of the can making more room for itself to expand


mark brainliest   :)

IceJOKER [234]3 years ago
5 0

Answer:

A...........................................

Explanation:

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How do you calculate the mass of an object accelerating at22.35m/s2 with a force of 120N
Arte-miy333 [17]

Answer:

The mass of object is calculated as 5.36 kg

Explanation:

The known terms to find the mass are:

           acceleration of object (a) = 22.35 m/s^{2}

                        Force exerted (F) = 120N

                        mass of an object (m) = ?

From Newton's second law of motion;

                                   F = ma

                           or, 120 = m × 22.35

                          or, m= \frac{120}{22.35} kg

                           ∴ m = 5.36 kg

3 0
2 years ago
The electric force between two charged balloons is 0.12 newtons. If the distance between the two balloons is halved, what will b
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Answer:

The answer is D, I just took the test

Explanation:

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3 years ago
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2 years ago
87) Determine the equivalent resistances for the following circuits.
stepladder [879]

Answer:

15    and  11 ohms

Explanation:

First one =   For the parallel resistors 1 / (1/6 + 1/6 + 1/6) =   1/ (3/6 ) = 6/3 = 2 ohms   then add the 3 and the 10  = 15 ohms

second one    for the parallel portion   equiv =    (10+2)*24 / ( (10+2 + 24) = 8

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8 0
2 years ago
An insulated piston–cylinder device contains 100 L of air at 400 kPa and 25°C. A paddle wheel within the cylinder is rotated unt
solong [7]

Answer:

T'=70.92°C

Explanation:

Given that

V= 100 L=0.1 m³

P=400 KPa

T=25°C

Work done on the air = 15 KJ

W= -15 KJ

If we assume that air is ideal gas

P V = m R T

R=0.287 KJ/kg.K for air

T= 273 + 25 = 298 K

By putting the values

P V = m R T

400 x 0.1 = m x 0.287 x 298

m=0.46 kg

From first law of thermodynamics

Q= ΔU +W

Insulated piston–cylinder  , Q=0

ΔU  = m Cv  ΔT

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Cv = 0.71 KJ/kg.k for air

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T'=70.92 °C

So the final temperature of air is T'=70.92 °C

7 0
3 years ago
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