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3 years ago

Why does the liquid rise up through the dip tube when the valve is open

2 answers:

6 0

The liquid rise up through the dip tube when the valve is opened. The propellant gas wants to expand as much as it can, so if the valve is open, the propellant expands and pushes the spray up out of the can making more room for itself to expand

mark brainliest :)

IceJOKER [234]3 years ago

5 0

Answer:

A...........................................

Explanation:

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Dana has a sports medal suspended by a long ribbon from her rearview mirror. As she accelerates onto the highway, she notices th

ivann1987 [24]

Answer:

$2.26m/s^2$

Explanation:

Suppose the tension in the ribbon is T.

The upwards component of the tension = Tcos13

The horizontal component of the tension = Tsin13

The weight of the medal = mg

In a vertical direction, mg is balanced by Tcos13, so mg=Tcos13, so T = mg/cos13. The horizontal component of T is the force causing m to accelerate.

$F = ma\\T\sin13^{\circ} = ma$

Substituting T= mg/cos13 gives:

$\frac{mg}{cos13^{\circ}}sin13^{\circ} = ma$

$m$ cancels and you have

$g\tan13 = a\\a=9.81\tan13^{\circ} \approx 2.26m/s^2$

7 0

4 years ago

you are running out and the first mike takes 10 minutes the second mile takes you 20 minutes this is an example of

4vir4ik [10]

Answer:

??????

Explanation:

4 0

3 years ago

Read 2 more answers

1. Consider the position vs time graph at right.

Lemur [1.5K]

Answer:

Labor Day Weekend--No School

9/1/2021

Hello Students!

There will be no School on Friday Sept 3 and Monday Sept 6

All centers will be closed on Friday 9/3 and Monday 9/6

School will resume on TUESDAY, Sept 7

Enjoy your long weekend!

Explanation:

Labor Day Weekend--No School

9/1/2021

Hello Students!

There will be no School on Friday Sept 3 and Monday Sept 6

All centers will be closed on Friday 9/3 and Monday 9/6

School will resume on TUESDAY, Sept 7

Enjoy your long weekend!

5 0

3 years ago

Para instalar una antena de televisor, se utilizó un poste de 10 metros de altura y se emplearon 30m de alambre que se sujetaron

Oxana [17]

Answer:

To install a television antenna, a 10-meter-high pole was used and 30m of wire were used, which were attached to an eye bolt installed on the ground. Determine the distance between the eyelet and the base of the post

5 0

3 years ago

Very large accelerations can injure the body, especially if they last for a considerable length of time. The severity index (SI)

Ludmilka [50]

Answer:

a) The severity index (SI) is 3047.749, b) The injured travels 0.345 meters during the collision.

Explanation:

a) The g-multiple of the acceleration, that is, a ratio of the person's acceleration to gravitational acceleration, is:

$a' = \frac{35\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

$a' = 3.569$

The time taken for the injured to accelerate to final speed is given by this formula under the assumption of constant acceleration:

$v_{f} = v_{o} + a \cdot t$

Where:

$v_{o}$ - Initial speed, measured in meters per second.

$v_{f}$ - Final speed, measured in meter per second.

$a$ - Acceleration, measured in $\frac{m}{s^{2}}$ .

$t$ - Time, measured in seconds.

$t = \frac{v_{f}-v_{o}}{a}$

$t = \frac{\left(12\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)}{35\,\frac{m}{s^{2}} }$

$t = 0.095\,s$

Lastly, the severity index is now determined:

$SI = \frac{a'^{5}}{2\cdot t}$

$SI = \frac{3.569^{5}}{2\cdot (0.095\,s)}$

$SI = 3047.749$

b) The initial and final speed of the injured are $1.944\,\frac{m}{s}$ and $5.278\,\frac{m}{s}$ , respectively. The travelled distance can be determined from this equation of motion:

$v_{f}^{2} = v_{o}^{2} + 2\cdot a \cdot \Delta s$

Where $\Delta s$ is the travelled distance, measured in meters.

$\Delta s = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}$

$\Delta s = \frac{\left(5.278\,\frac{m}{s} \right)^{2}-\left(1.944\,\frac{m}{s} \right)^{2}}{2\cdot \left(35\,\frac{m}{s^{2}} \right)}$

$\Delta s = 0.345\,m$ .

8 0

3 years ago