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astra-53 [7]
3 years ago
6

Label the three forms of energy represented in this image

Physics
2 answers:
Stells [14]3 years ago
8 0

Answer:

Where is this image?

Greeley [361]3 years ago
4 0
The image is not showing up.
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Suppose a treadmill has an average acceleration of 4.7x10^-3 m/s. a)how much does its speed change after 5min? b)if the treadmil
Mars2501 [29]

Answer:

a)Change in the speed  = 1.41 m/s

b)The final speed will be 3.11 m/s

Explanation:

Given that

Acceleration ,a= 4.7 x 10⁻³ m/s²

a)

We know that

v= u + a t

v=final speed ,u=initial speed

t= time ,a= acceleration

Change in the speed

v- u = a t

t= 5 min  = 5 x 60 s = 300 s

v- u = 4.7 x 10⁻³ x 5 x 60 m/s

v-u = 1.41 m/s

Change in the speed  = 1.41 m/s

b)

Given that

u= 1.7 m/s

v-u = 1.41 m/s

v= 1.7 + 1.41 m/s

v=3.11 m/s

The final speed will be 3.11 m/s

8 0
3 years ago
Please help :)<br> i would rlly appreciate it :)))
algol [13]

Answer:

the answer for that is "A"

6 0
3 years ago
Considering this analogy (current = rate that heat flows through a window, and voltage = temperature difference across the windo
erastovalidia [21]

Answer:

Explained

Explanation:

Resistance R in a current flow through an object is given by

R= \frac{\rho L}{A}

ρ = resistivity of the material

L= length of the object

A=  area of cross section

clearly resistance is directly dependent on length of the object.This means greater the length larger will be resistance to current.

thermal resistance R_th is given by

R_{th} = \frac{L}{KA}

L= length of the object

A=  area of cross section

K = Conductivity of the material

thermal resistance is also is directly dependent on length of the object.This means greater the length larger will be resistance to current.

8 0
3 years ago
Read 2 more answers
Is 5g greater than 20.43 mg
worty [1.4K]

yes that's true 6g is larger

4 0
3 years ago
Read 2 more answers
A spinning wheel is slowed down by a brake, giving it a constant angular acceleration of ?5.20 rad/s2. during a 3.80-s time inte
ddd [48]

<span>We can answer this using the rotational version of the kinematic equations:</span><span>
θ = θ₀ + ω₀<span>t + ½αt²     -----> 1</span></span>

ω² = ω₀² + 2αθ            -----> 2

Where:

θ = final angular displacement = 70.4 rad

θ₀ = initial angular displacement = 0

ω₀ = initial angular speed

ω = final angular speed

t = time = 3.80 s

α = angular acceleration = -5.20 rad/s^2

Substituting the values into equation 1:<span>
70.4 = 0 + ω₀(3.80) + ½(-5.20)(3.80)² </span><span>

ω₀ = (70.4 + 37.544) / 3.80 </span><span>

ω₀ = 28.406 rad/s </span><span>


Using equation 2:
ω² = (28.406)² + 2(-5.2)70.4 


ω = 8.65 rad/s 


</span>

5 0
3 years ago
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