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max2010maxim [7]
3 years ago
13

Elapsed time 50 minutes.ending time 9:05 am find starting time

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

8:15 am

Step-by-step explanation:

Count back from 9:05 50 minutes. I did it in parts.

First, I went back 5 minutes:

9:05 am 50 minutes elapsed

9:00 am 45 minutes elapsed

Then I went back the rest of the 45 minutes

9:00 am 45 minutes elapsed

8:15 am 0 minutes elapsed

Serggg [28]3 years ago
8 0

9:05-:05= 9:00-:45=8:15

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Find the equation of the line through (5,7) that is perpendicular to y=2/3x-2
Rainbow [258]

Answer:

y=-2/3x+10.3333333333333334

Step-by-step explanation:

to make it perpendicular 2/3 becomes -2/3

4 0
3 years ago
Read 2 more answers
5 more than 3 times a variable, x, is 23
Monica [59]

3x + 5 = 23

5 more than(addition) 3 times(multiplication) a variable(x) is(equals) 23

(you add 5 to 3x)

If you need to solve for "x", you need to isolate/get the variable "x" by itself in the equation:

3x + 5 = 23        Subtract 5 on both sides

3x + 5 - 5 = 23 - 5

3x = 18      Divide 3 on both sides to get "x" by itself

\frac{3x}{3} =\frac{18}{3}

x = 6

5 0
3 years ago
3tanx3x=3 square rooted<br>​
torisob [31]

Answer:

\tan 3x=\frac{\sqrt{3} }{3} =\frac{1}{\sqrt{3} } =tan\frac{\pi }{6} =tan (n\pi +\frac{\pi }{6} )\\3x=n\pi +\frac{\pi }{6} =\frac{(6n+1)\pi }{6} \\x=\frac{(6n+1)\pi }{18} \\where~x~is~an~integer.

Step-by-step explanation:

tan 3x=\frac{\sqrt{3} }{3} =\frac{1}{\sqrt{3} } =tan\frac{\pi }{6} =tan (n\pi +\frac{\pi }{6} )\\3x=n\pi +\frac{\pi }{6} =\frac{(6n+1)\pi }{6} \\x=\frac{(6n+1)\pi }{18} \\

where~x~is~an~integer.

6 0
2 years ago
If a triangle has side lengths 7, 10, and 12, is it a right triangle??
Vesnalui [34]

Answer:

No. Remember, a right angle must have a 90 degree angle. We can find the lengths with the Pythagorean Theorem.

Step-by-step explanation:

Given the length 7, 10, and 12, we can assume that 12 is the hypotenuse (it is the longest length).

- we can use 7 and 10 interchangeably.

Fill in the equation, a^2 + b^2 = c^2

                 where c = 12, and a or b = 7 or 10.

To indicate if the given lengths would form a right angle, we can only input 7 or 10, not both.

Therefore, 7^2 + b^2 = 12^2 or 10^2 + b^2 = 12^2

7^2 + b^2 = 12^2 ==> 49 + b^2 = 144 ==> <u>b= </u>\sqrt{95<u> ==> </u><u>9.746</u>

b= 9.7, not 10.

10^2 + b^2 = 12^2 ==> 100 + b^2 = 144 ==> <u>b = </u>\sqrt{44<u> ==> </u><u>6.633 </u>

b= 6.6, not 7.

Therefore, the lengths 7, 10, and 12, does NOT make a right triangle.

Hope this helps!

5 0
3 years ago
A rectangle has an area of 0.24 of a square. What are some possibility for the length and width of the rectangle? Tell why
VLD [36.1K]

Answer:

<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>

Step-by-step explanation:

Given that the area is 0.24 square meter

The area of a rectangle is given by

Area=length\times width square units

Let x be the length and y be the width.

Since the area is 0.24 square meter, we have the equation:

Area=x\times y = 0.24, with x and y measures in meters

If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.

Now choosing some values for "x", we have:

Put x = 1

1\times y = 0.24

∴ y = 0.24

Now put x = 0.5 we get

0.5\times y = 0.24

∴ y = 0.48

Put  x = 0.25

0.25\times y = 0.24

∴ y = 0.96

Put x = 2

2\times y = 0.24

∴ y = 0.12

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2 years ago
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