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Elenna [48]
2 years ago
14

I need help -3x-(2x+6)

Mathematics
2 answers:
tresset_1 [31]2 years ago
3 0

Answer:

−5−6

Step-by-step explanation:

Hope this helps c:

Lemur [1.5K]2 years ago
3 0

Answer:

-5x - 6

Step-by-step explanation:

-3x - ( 2x + 6 )

Distribute the (-) sign

-3x - ( 2x + 6 )

-3x - 2x - 6

Simplify

-3x - 2x - 6

-5x - 6

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Im really stuck on this............
Len [333]

Answer:

H is the Answer

Step-by-step explanation:

Apply distance formula.

(x {}^{2  } -  {x}^{1}  ) {}^{2}  + ( {y}^{2}  -  {y}^{1} ) {}^{2}  = d {}^{2}

where d is the distance.

( - 5 - 7) {}^{2}  + (0 - 5) {}^{2}  =

- 12 {}^{2}  +  - 5 {}^{2}  =  {d}^{2}

\sqrt{169}  =  {d}^{2}

d = 13

3 0
3 years ago
Read 2 more answers
Each of 3 bags contains x pencils. Tyler adds 2 more pencils to each bag. Altogether, the gift bags contain 12 pencils.
WARRIOR [948]

Answer:

Below

Step-by-step explanation:

5 0
3 years ago
HelloI need some assistance with this question. I provided an answer, but it was incorrect. The images are enclosed.
ycow [4]

Given:

There are given that the zeroes and degrees of the polynomial:

\begin{gathered} \text{zeros:}-2,2,4 \\ \text{Degres:}3 \end{gathered}

Explanation:

From the concept of a polynomial:

A polynomial has a as zero if and only if (x -a) is a factor of the polynomial.

Then,

From the given polynomial:

f(x)=(x+2)(x-2)(x-4)

Then,

\begin{gathered} f(x)=(x+2)(x-2)(x-4) \\ f(x)=(x^2-2x+2x-4)(x-4) \\ f(x)=(x^2-4)(x-4) \\ f(x)=x^3-4x^2-4x+16 \end{gathered}

Final answer:

Hence, the polynomial is shown below:

f(x)=x^3-4x^2-4x+16

6 0
1 year ago
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8 0
3 years ago
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
3 years ago
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