Answer:
its horizontal asympotote is when y<=1
Hey there! :)
Answer:
(2, -2)
Step-by-step explanation:
-2x + y = -6
4x + 3y = 2
We can begin by setting the first equation equal to y:
-2x + y = -6
Add 2x to both sides:
y = 2x - 6
Plug this equation for y into the second equation:
4x + 3(2x - 6) = 2
Distribute:
4x + 6x - 18 = 2
Combine like terms:
10x = 20
x = 2
Plug the value of 'x' into an equation to solve for 'y':
-2(2) + y = -6
-4 + y = -6
y = -2
Therefore, the solution is (2, -2)
Answer:
y = 0.5 (x^2 -2x + 16) has a y-intercept of 8.
Step-by-step explanation:
The x-coordinate of every y-intercept is zero. To determine which of the four quadratics given here has a y-intercept of 8, we need only substitute 0 for x in each; if the result is 8, we've found the desired quadratic.
O y = 0.5(x + 2)(x + 4) becomes y = 0.5(2)(4) = 4 (reject this answer)
O y = 0.5 (x - 2)(x + 8) becomes y = 0.5(-2)(8) = -8 (reject)
O y = 0.5(x2 -2x - 16) becomes y = 0.5(-16) = -8 (reject)
<em>O y = 0.5 (x2 -2x + 16) becomes y = 0.5(16) = 8 This is correct; that '8' represents the y-intercept (0, 8).</em>
I think it is F, but I am a not sure.
Answer:
the last one
Step-by-step explanation:
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