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zheka24 [161]
3 years ago
14

What is the sum of (5m+9)+(9b-3)+(8c+6) simplified

Mathematics
1 answer:
Vlad [161]3 years ago
7 0
5m+9b+8c+12.....i think ? lolz
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Will mark brainlist plz anwser
never [62]
The width of the court is 30 feet!
5 0
3 years ago
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188 to 42 what is the percent change
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

so we are gonna have a percent decrease because it went from 188 to 42

decrease = (original number - new number) / (original number ) * 100

                = (188 - 42) / (188) * 100

                = (146 / 188) * 100

                = 0.7766 * 100

                = 77.66% decrease....not sure if u need ur answer rounded to the nearest percent or not....if so, its a 78% decrease

6 0
3 years ago
What should be subtracted from -9876 to obtain -9512​
Sliva [168]

Answer:

-364 should be subtracted

Step-by-step explanation:

subtract -9876 from -9512 to see what number u will get and them that's the number that will obtain -9512

-9876

-9512

_

_______

-364

-9876

-364

_

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-9512

5 0
3 years ago
Read 2 more answers
I didn’t pay attention in class help
Alona [7]

Answer:

The 1/4th power means the 4th root of a number.

Therefore for the first question, the answer should be 4th root of 1296 -4th root of 625. or \sqrt[4]{1296}

4

1296

-\sqrt[4]{625}

4

625

:D

For the second question just calculate? what to the 4th power is 1296 and what to the 4th power is 625?

They should respectively be 6 and 5. So the final answers we get is 6-5=1

If you have any questions about this just ask me in the comment and I will get to it as soon as I could.

hopecthis helps

4 0
3 years ago
COF
Flauer [41]

Answer:

X \sim N(\mu= 70, \sigma=15)

From this info and using the empirical rule we know that we will have about 68% of the scores between:

\mu -\sigma = 70-15=55

\mu +\sigma = 70+15=85

95 % of the scores between:

\mu -2\sigma = 70-2*15=40

\mu +2\sigma = 70+2*15=100

And 99.7% of the values between

\mu -3\sigma = 70-3*15=25

\mu +3\sigma = 70+3*15=115

Step-by-step explanation:

For this problem we can define the random variable of interest as "the student grades" and we know that the distribution for X is given by:

X \sim N(\mu= 70, \sigma=15)

From this info and using the empirical rule we know that we will have about 68% of the scores between:

\mu -\sigma = 70-15=55

\mu +\sigma = 70+15=85

95 % of the scores between:

\mu -2\sigma = 70-2*15=40

\mu +2\sigma = 70+2*15=100

And 99.7% of the values between

\mu -3\sigma = 70-3*15=25

\mu +3\sigma = 70+3*15=115

5 0
3 years ago
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