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3 years ago

ASAP I need help with this

Mathematics

2 answers:

lesya692 [45]3 years ago

8 0

Answer: the first one

Step-by-step explanation: Hwo i think of it is if you have to fill in the circle then you have to draw a line under the greater than or less than sign, so the more you have to do on each if that makes sense!

Annette [7]3 years ago

4 0

Answer:

its A

Step-by-step explanation:

If its one of these signs(<>) then its open and if its one of the signs with the line under it then its closed

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A circle has a circumference of 6. it has an arc of length 1/3

Maksim231197 [3]

Answer:

Ф = 10°

Step-by-step explanation:

Regarding arc length, s: s = r·Ф, where Ф is the central angle in radians and r is the radius.

We need to find the central angle, Ф, in this problem.

We know that C = circumference = 6, and that this leads to r = 6/π.

Substituting 6/π for r and 1/3 for s in Ф = s / r, we get:

Ф in radians = 1/3 / (6/π), or Ф = π/18 rad.

π 180°

Converting this into degrees, we multiply ------ by ----------

18 π rad

obtaining: Ф = 10°

3 0

3 years ago

Read 2 more answers

Please help will give brainliest

Ivanshal [37]

The answer will be A

5 0

3 years ago

(2/3v)^-3 for v=9 I don't understand how to find the answer. will you help me?

natta225 [31]

V=square root (3/2)/2
Or V=-square root (3/2)/2

8 0

3 years ago

Hello help me with this question thanks in advance

Ede4ka [16]

$\bold{\huge{\green{\underline{ Solutions }}}}$

<h3>Answer 11 :-</h3>

We have, 

$\sf{HM = 5 cm }$

In square all sides of squares are equal

The perimeter of square 

$\sf{ = 4 × side }$

$\sf{ = 4 × 5 }$

$\sf{ = 20 cm }$

Thus, The perimeter of square is 20 cm

Hence, Option C is correct .

<h3>Answer 12 :-</h3>

We have, 

$\sf{MX = 3.5 cm }$

In square, diagonals are equal and bisect each other at 90°

Here, 

$\sf{MX = MT/2}$

$\sf{MT = 2 * 3.5 }$

$\sf{MT = 7 cm}$

Thus, The MT is 7cm long

Hence, Option C is correct .

<h3>Answer 13 :- </h3>

We have to find the measure of Angle MAT

All angles of square are 90° each

From above

$\sf{\angle{MAT = 90° }}$

Thus, Angle MAT is 90°

Hence, Option B is correct .

<h3>Answer 14 :-</h3>

We know that, 

All the angles of square are equal and 90° each

Therefore, 

$\sf{\angle{MHA = }}{\sf{\angle{ MHT/2}}}$

$\sf{\angle{MHA = 90°/2}}$

$\sf{\angle {MHA = 45°}}$

Thus, Angle MHA is 45°

Hence, Option A is correct

<h3>Answer 15 :- </h3>

Refer the above attachment for solution

Hence, Option A is correct

<h3>Answer 16 :- </h3>

Both a and b

The median of isosceles trapezoid is parallel to the base
The diagonals are congruent

Hence, Option C is correct

<h3>Answer 17 :-</h3>

In rhombus PALM,

All sides and opposite angles are equal

Let O be the midpoint of Rhombus PALM

In ΔOLM, By using Angle sum property :-

$\sf{35° + 90° + }{\sf{\angle{ OLM = 180°}}}$

$\sf{\angle{OLM = 180° - 125°}}$

$\sf{\angle{ OLM = 55° }}$

Now, 

$\sf{\angle{OLM = }}{\sf{\angle{OLA}}}$

OL is the bisector of diagonal AM

Therefore, 

$\sf{\angle{ PLA = 55° }}$

Thus, Angle PLA is 55° .

Hence, Option C is correct

8 0

3 years ago

HELPPPP Solve for x using the figure to the right.

Maurinko [17]

Answer:

x = 20 units

Step-by-step explanation:

By geometric mean theorem:

${x} = \sqrt{40 \times 10} \\ \\ \implies{x} = \sqrt{400} \\ \\ \implies{x} = 20 \: units \\ \\$

7 0

2 years ago

ASAP I need help with this ​

ASAP I need help with this