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rodikova [14]
3 years ago
7

From 95 books to 116 books

Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0

Answer:

21 books were added

Hope I helped,

PumpkinSpice1

☼♥☼♥☼♥☼♥☼

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Write down the coordinates of the image of the point (2-3) under reflecting about the line joining the points (3, 5) and (3,7) ​
Murrr4er [49]

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(4 , -3)

Step-by-step explanation:

the points (3 , 5) and (3 , 7) ​have the same x-coordinates 3

then ,the line D joining them has the equation  

D : x = 3

the image of the point A(2 , -3) under reflecting about The line D ,

lie on the line ∆ perpendicular to D and passes through A.

∆ perpendicular to D then the equation of ∆ is :

∆ : y = a   ,where a is a real number.

Calculating ‘a’ :

∆ passes through A

Then

-3 = a

Therefore

the final equation of ∆ is :

∆ : y = -3

Obviously, the lines D and ∆ intersect at the point M(3 , -3)

FINAL STEP :

<u><em>Calculating the coordinates of the point B(x , y) image of the point A(2 , -3) </em></u>

M is the midpoint of the line segment AB :

Then

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The given logarithmic expression is:

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This is the same as:

\frac{1}{3}\log(3x)+ \frac{1}{3}\log(3x)^2

\frac{1}{3}(\log(3x)+ \log(3x)^2)

We now apply the product rule to get:

\frac{1}{3}\log(3x)\times (3x)^2

\frac{1}{3}\log (3x)^3

We now apply the power rule to get;

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3 years ago
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