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vovikov84 [41]
3 years ago
7

carlos es un arquitecto y esta construyendo una casa si ha construido 3/7 de la casa le falta para acabarla es lo mismo que lleg

ar a 7/7​
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

Ok, sabemos que Carlos ha construido un 3/7 de una casa.

Queremos saber cuanto le falta para terminar de construirla.

Entonces podemos realizar el cálculo:

1 casa - lo que Carlos ya construyo = Lo que le falta.

Entonces:

1 casa - 3/7 de una casa = X

Podemos reescribir:

1 casa = 7/7 de una casas

así tenemos:

7/7 de una casa  - 3/7 de una casa = X

(7/7 - 3/7) de una casa = X

4/7 de una casa  = X

Así podemos concluir que a Carlos le falta construir 4/7 de una casa para acabar.

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