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mr_godi [17]
3 years ago
9

A 10 kilogram sled is pulled across a frictionless surface with a force of 50 newtons for a distance of 10 meters. The pull is a

pplied to the sled for a time of 2.0 seconds.
Physics
1 answer:
Gala2k [10]3 years ago
8 0

Answer:

The power will be "250 watt". A further explanation is given below.

Explanation:

The given values are:

Force,

F = 50 N

Displacement,

d = 20 m

Time,

t = 2.0 seconds

Whenever the block is pulled, the angle will be "0" i.e., Cos0° = 1

Now,

The work will be:

= Force\times displacement\times \Theta

On substituting the given values, we get

= 50\times 10\times Cos0^{\circ}

= 50\times 10\times 1

= 500 \ Newton

Now,

The Power will be:

= \frac{Work \ done}{time}

= \frac{500}{2.0}

= 250 \ watt

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