Question

A 10 kilogram sled is pulled across a frictionless surface with a force of 50 newtons for a distance of 10 meters. The pull is applied to the sled for a time of 2.0 seconds.

Answer 1

Answer:

The power will be "250 watt". A further explanation is given below.

Explanation:

The given values are:

Force,

F = 50 N

Displacement,

d = 20 m

Time,

t = 2.0 seconds

Whenever the block is pulled, the angle will be "0" i.e., Cos0° = 1

Now,

The work will be:

= $Force\times displacement\times \Theta$

On substituting the given values, we get

= $50\times 10\times Cos0^{\circ}$

= $50\times 10\times 1$

= $500 \ Newton$

Now,

The Power will be:

= $\frac{Work \ done}{time}$

= $\frac{500}{2.0}$

= $250 \ watt$