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Alex_Xolod [135]
2 years ago
9

A ball was dropped from a height of 10 feet. Each time it hits the ground, it bounces 4/5 of its previous height. Find the total

distance traveled by the bouncing ball.
Physics
1 answer:
Shtirlitz [24]2 years ago
8 0

Answer:

d = 90 ft

Explanation:

As we know that after each bounce it reaches to 4/5 times of initial height

so we can say

h_2 = \frac{4}{5}h

so the distance covered is given as

d = h + 2(\frac{4}{5}h) + 2(\frac{4}{5})^2h + 2(\frac{4}{5})^3h........

here we know that

h = 10 feet

d = h + 2(\frac{4}{5}h)(1 + \frac{4}{5} + (\frac{4}{5})^2 + ...........)

d = 10 + 2(\frac{4}{5}(10))(\frac{1}{1 - \frac{4}{5}})

d = 90 ft

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WARRIOR [948]

Answer:

ANS : .Energy spent on spraying =4.3542*10^{-4}J

Explanation:

<em>Given:</em>

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Thus, volume is conserved.

i.e ,

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Where ,

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Initial energy E_{i} = T*A_{i}\\= 0.0035 * 4 *\pi *0.01^{2}\\=4.398*10^{-6}J

Final energy E_{f}=10^{6}*T*A_{f}\\=10^{6}*0.0035*4*\pi *(0.0001)^2\\=4.39823*10^{-4}

∴  .Energy spent on spraying = =E_{f}-E{i}\\=(439.823-4.39823)*10^{-6}\\=4.3542*10^{-4}J

ANS : .Energy spent on spraying =4.3542*10^{-4}J

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The distance, in feet, a moving object has traveled after t seconds is given by 2t/(4 + t). find the acceleration of the object
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Hi! Let me help you!
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