Answer:
a_total = 2 √ (α² + w⁴)
, a_total = 2,236 m
Explanation:
The total acceleration of a body, if we use the Pythagorean theorem is
a_total² = a_T²2 +
²
where
the centripetal acceleration is
a_{c} = v² / r = w r²
tangential acceleration
a_T = dv / dt
angular and linear acceleration are related
a_T = α r
we substitute in the first equation
a_total = √ [(α r)² + (w r² )²]
a_total = 2 √ (α² + w⁴)
Let's find the angular velocity for t = 2 s if we start from rest wo = 0
w = w₀ + α t
w = 0 + 1.0 2
w = 2.0rad / s
we substitute
a_total = r √(1² + 2²) = r √5
a_total = r 2,236
In order to finish the calculation we need the radius to point A, suppose that this point is at a distance of r = 1 m
a_total = 2,236 m
Explanation:
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Two small spheres spaced 20.0 cm apart have equal charge.
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57 x 10-21 N?
Number of Electrons = ?
Answer:
a.) 2.66 seconds for 79.2 km/h and 1.82 seconds for 47.8 km/h
b.)-4.13 m/s2 for 79.2 km/h and -3.63 m/s2 for 47.8 km/h
Explanation:
Now for (a)
time = velocity/distance
for velocity = 79.2 km/h and distance 0.0586 km
t = (0.0586/79.2)*3600
t = 2.66 seconds (Please note that multiplication with 3600 is to convert hours into seconds)
for velocity 47.8 km/h and distance 0.0242 km
t = (0.0242/47.8)*3600
t = 1.82 seconds
Now for (b)
2as = vf2-vi2
so,
2a(58.6) = -(79.2*1000/3600)^2 (Please note that multiplication and division with 1000 and 3600 respectively is to convert speed unit from km/h to m/s)
a = -4.13 m/s2 for 58.6 m
and
2a(24.2) = -(47.8*1000/3600)^2
a = -3.63 m/s2 for 24.2 m.
Please note that "-" sign express the deceleration.