Move all terms that don't contain x to the right side and solve.
x=−5/3−y/3
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There are 18 girls in the class and 6 boys.
Answer:
Use Math site
Step-by-step explanation: Math way
-6x-4(-7x-13)=-58
Multiply the bracket by -4
-6x-4(-7)-4(-13)= -58
-6x+28x+52= -58
22x+52= -58
Move +52 to the other side. Sign changes from +52 to -52.
22x+52-52= -58-52
22x= -110
Divide by 22.
22/22x= -110/22
x= -5
Answer: x= -5
Answer:
Marginal revenue = R'(Q) = -0.6 Q + 221
Average revenue = -0.3 Q + 221
Step-by-step explanation:
As per the question,
Functions associated with the demand function P= -0.3 Q + 221, where Q is the demand.
Now,
As we know that the,
Marginal revenue is the derivative of the revenue function, R(x), which is equals the number of items sold,
Therefore,
R(Q) = Q × ( -0.3Q + 221) = -0.3 Q² + 221 Q
∴ Marginal revenue = R'(Q) = -0.6 Q + 221
Now,
Average revenue (AR) is defined as the ratio of the total revenue by the number of units sold that is revenue per unit of output sold.

Where Total Revenue (TR) equals quantity of output multiplied by price per unit.
TR = Price (P) × Total output (Q) = (-0.3Q + 221) × Q = -0.3 Q² + 221 Q


∴ Average revenue = -0.3Q + 221