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Sergeeva-Olga [200]
3 years ago
11

7 Simplify the expressionby combining like terms 3g+ 21439 +40 +41 =

Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0

\huge\text{Hey there!}

\large\textsf{3g + 21,439 + 40 + 41}

\large\text{COMBINE the LIKE TERMS}

\large\textsf{(21,439 + 40 + 41) + (3g) }

\large\textsf{21,439 + 40 + 41}\\\large\textsf{21,439 + 40 = \bf 21, 479}\\\large\textsf{21,479 + 41}\\\large\textsf{= \bf 21,520}

\large\textsf{3g = \bf 3g}

\large\textsf{= \bf 3g + 21, 520}

\boxed{\boxed{\large\textsf{Answer: \huge \bf 3g + 21,520}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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Answer:

s^2 = \frac{(1.48-1.502)^2 +(1.45-1.502)^2 +(1.54-1.502)^2 +(1.52-1.502)^2 +(1.52-1.502)^2}{5-1} =0.00132

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Step-by-step explanation:

For this case we have the following data:

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The first step for this cae is find the sample mean with the following formula:

\bar X =\frac{\sum_{i=1}^n X_}{n}

And replacing we got:

\bar X= \frac{1.48+1.45+1.54+1.52+1.52}{5} = 1.502

And now we can calculate the sample variance with the following formula:

s^2 =\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And replacing we got:

s^2 = \frac{(1.48-1.502)^2 +(1.45-1.502)^2 +(1.54-1.502)^2 +(1.52-1.502)^2 +(1.52-1.502)^2}{5-1} =0.00132

And for the deviation we have:

s= \sqrt{0.00132}=0.0363

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