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Morgarella [4.7K]
2 years ago
13

Easy work! Please click on the photo and do 5. 10. 14. And 16.Also it’s is easy but only for other people not me just for people

asking.

Mathematics
1 answer:
horsena [70]2 years ago
4 0

Answer: the 1 is > the one below it is < the one next to it unknown

and the one next to it is > and the last one is =

branliyist please

Step-by-step explanation:

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Solve for <br> n<br> nn.<br> 7<br> n<br> −<br> 4<br> =<br> 31
makkiz [27]

Answer: 5

Step-by-step explanation:

5x7=35

35-4=31

5 0
2 years ago
Read 2 more answers
A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei
Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size  'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample  S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size  n₂ = 24</em>

<em>mean of the second sample  "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample  S₂ =  2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em>    </em>t = \frac{x^{-} _{1} -  x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} }  }

<em>    where         </em>S^{2}   = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2}   }{n_{1} +n_{2} -2}

                      S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}

<em>              substitute values and we get  S² =  40.988</em>

<em>     </em>t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24}  )}<em></em>

<em>  </em>   t =  1.3622

  Calculated value t = 1.3622

Tabulated value 't' =  2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em>      </em>

<em>                        </em>

<em>                    </em>

6 0
2 years ago
Solve by completing the square x^2-6x=1
Dmitry [639]
(x-3)^2=10
I hope this helps you.
4 0
3 years ago
Jericho takes 3 tests in one month. The number of correct answers and the total
Delvig [45]

Answer:

you need to show the table for this question to get solved

8 0
2 years ago
Read 2 more answers
A rectangular swimming pool is 50 feet long and 25 feet wide.
Scrat [10]

Answer:

Area = 1250 square feet

Step-by-step explanation:

The formula for area of the bottom of the pool is given by:

Area = length× breadth

          = 50 × 25

          =  1250 square feet

4 0
2 years ago
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