Going by the data given, the best center of distribution to use in terms of mean and median is D) Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric.
<h3>What centers of distribution should be used?</h3>
The mean should be used for data sets that are symmetric while the median should be used for data that is not symmetric.
The data is said to be symmetric when the mean and median are equal or very close.
Bakery A mean:
= (45 + 52 + 51 48 + 61 + 34 + 55 46) / 8
= 49
Bakery A median is 49.5
Bakery B mean:
= (48 42 + 25 45 + 57 + 10 + 43 + 46 ) / 8
= 39.5
Bakery B median is 44.
This shows that Bakery A data is symmetric so the best center of distribution to use is mean.
Bakery B is not symmetric so the center of distribution to use is median.
Find out more on symmetric data at brainly.com/question/7130507
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Answer:
11. 736080 cars // 12. 5397920 cars
Step-by-step explanation:
given total number of cars produced : 6,134,000
100% -->6,134,000
1%--> 6,134,000 /100
1% --> 61340
given big cars of America is 12%
so to find this 12% = 12 * 61340 = 736080 cars produced by America
by other manufactures = total cars - big cars of America
= 6,134,000 - 7,36,080
= 5397920 cars
It has to be 2.75 as a decimal.
