Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
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- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811
Correct answer is: (0,7843) and (10,8793)
Solution:-
Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.
We have to write this data as (x,y) .
Where x= years after 1990 and y=number of students enrolled.
Since in 1990, 7843 students enrolled, x = 1990-1990=0
And y=7843.
Hence one ordered pair is (0,7843).
Let us find the years after 1990 for 2000 = 2000-1990 =10
Hence another ordered pair is (10,8793).
