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lakkis [162]
3 years ago
8

Please check over this!! 20 points! easy fractions

Mathematics
2 answers:
sertanlavr [38]3 years ago
8 0
1:B
2:A
3: 3/7 
4: 2/11 for black, 1/11 blue, and 8/11 is the white

ladessa [460]3 years ago
3 0
1 is correct
2 is correct
3 is correct
4 is correct
5 is correct
6 is correct
7 is correct
8 is correct

Hoped I helped!








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I think it is 29 cause it’s in the 20’s while the others aren’t
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Find the magnitude and direction in degrees of the vector v=6i+2 seq31​
masha68 [24]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the vector

v = 6i + 2√3j

The Magnitude of a vector:

\mathrm{Computing\:the\:Euclidean\:Length\:of\:a\:vector}:\quad \left|\left(x_1\:,\:\:\ldots \:,\:\:x_n\right)\right|=\sqrt{\sum _{i=1}^n\left|x_i\right|^2}

=\sqrt{6^2+\left(2\sqrt{3}\right)^2}

=\sqrt{36+12}

=\sqrt{48}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

=\sqrt{3}\sqrt{2^4}

=4\sqrt{3}

The Direction of a vector:

tan Ф = y/x

y=2√3

x = 6

tan Ф = y/x

          = 2√3 / 6

           = √3 / 3                  

\theta \:=tan\:^{-1}\left(\frac{\sqrt{3}}{3}\right)

\:\theta \:=\frac{\pi \:}{6}=30^{\circ \:}

6 0
3 years ago
Whats the answer to this question?
forsale [732]

Answer:

0.67%

Step-by-step explanation:

2/300

3 0
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Read 2 more answers
Q # 4 Simplify the product
timama [110]
For this case we have the following product:
 (x-4) (x + 3)

 We must use the distributive property correctly to solve the problem.
 We have then:
 x ^ 2 + 3x - 4x - 12

 Then, we must add similar terms.
 We have then:
 x ^ 2 - x - 12

 Answer:
 
The final product is given by:
 
x ^ 2 - x - 12

 option 2
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3 years ago
What is an equation of the line that passes through the point ( 6 , − 2 ) (6,−2) and is perpendicular to the line 6 x + y = 2 6x
Diano4ka-milaya [45]

Answer:

An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

  • y=\frac{1}{6}x-3

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Given the line

6x+y=2

Simplifying the equation to write into the  slope-intercept form

y = -6x+2

So, the slope = -6

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus, the slope of the perpendicular line will be: -1/-6 = 1/6

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be

y-y_1=m\left(x-x_1\right)

substituting the values m = 1/6 and the point (6, -2)

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subtract 2 from both sides

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y=\frac{1}{6}x-3

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

  • y=\frac{1}{6}x-3
5 0
3 years ago
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