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Tanya [424]
3 years ago
7

When heated, calcium carbonate decomposes according to the equation given below:

Chemistry
1 answer:
Margaret [11]3 years ago
5 0

Answer:

Percent yield = 90.9%

Explanation:

Given data:

Mass of CaCO₃ = 50.0 g

Mass of CO₂ produced = 20.0 g

Percent yield = ?

Solution:

Chemical equation:

CaCO₃ →  CaO + CO₂

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 50.0 g/ 100.1 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of CO₂ with CaCO₃.

                      CaCO₃          :        CO₂

                          1                :           1

                       0.5               :          0.5

Mass of CO₂: Theoretical yield

Mass = number of moles × molar mass

Mass = 0.5 mol × 44 g/mol

Mass = 22 g

Percent yield:

Percent yield = ( actual yield / theoretical yield ) × 100

Percent yield = (20.0 g/ 22.0 g) × 100

Percent yield = 0.909 × 100

Percent yield = 90.9%

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Determine the molar solubility of pbso4 in pure water. ksp (pbso4 = 1.82 × 10-8.
Semenov [28]
Salts dissociate when dissolved in water:

PbSO4 -> Pb2+ + SO4 2-

So there are 2 different particles. 1 mol of PbSO4 produces 1 mol of Pb2+, and 1 mol of SO4 2- (one of each).

Kps = [Pb2+] [SO4 2-]

We will call “s” the molarity of PbSO4

So the molarity of Pb2+ is also “s” (same number)

And the molarity of SO4 2- is also “s” (same number)

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1.82 × 10-8 = s2

So, in order to find s, we have to make the square root of 1.82 × 10-8, which is: 0,00013491 M

7 0
4 years ago
Compounds A and BB are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 gg of su
Lelechka [254]

Answer:

Mass ratio of sulfur and oxygen in compounds A and B is 3:2 which confirms that the mass ratios in the two compounds are simple multiples of each other

Explanation:

This question seeks to establish/confirm the law of multiple proportions which  posits that elements combine to form different substances which are whole number multiples of each other. Best example of this plays out in the formation of several oxides of the same element. Looking at the ratio in which the elements combine in each of the oxides, we can assume that these ratios are simple whole number multiples of each other.

Now back to the question.

In substance A, we have 6 g of sulfur combining with 5.99 g of oxygen

Now, lest us calculate the ratio of the mass of sulfur to that of oxygen = 6g/5.99g = 1

Now let us calculate the mass ratio of sulfur to oxygen in the second compound = 8.6/12.88 = 0.668

Now the ratios in both compounds are 1 to 0.668. 0.668 to fraction is approximately 1/1.5.

So therefore, the ratio we are having would be 1:1/1.5 or 1:0.668

This is same as 1/(1÷1.5) which is 1.5/1 or simply 3/2

This gives a ratio of approximately 1.5 to 1 or 3 to 2

The ratio 3 to 2 indicates that the mass ratios in both com pounds are simple multiples of each other

5 0
4 years ago
What’s the formula for the reactant BaO(s)
fredd [130]

Answer:

2BA + 0 =2BAo

2

Explanation:

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4 0
3 years ago
What is the most complete answer below about the information, found about the element uranium in the periodic table
jonny [76]

Answer:

92 is that atomic number and 238.03 is the atomic mass number

Explanation:

The structure of the atom is given as:

                    ⁹²₂₃₈.₀₃U

The number 92 is the atomic number of the atom.

  The atomic number is the number of protons within an atom. This number defines the nature and type of atom that we have.

238.03 is the atomic mass number;

  The is the number of protons and neutrons within an atom. It is typically the mass of nucleus.

6 0
3 years ago
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