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3 years ago

Why does sodium form a 1+ ion but magnesium forms a 2+ ion

1 answer:

6 0

Because Na has one too many electron to be stable, while Mg has 2. once they loose those electrons, they will be come ion. loosing one electron will give the ion a 1+ charge, and loosing 2 will create a 2+ charge

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A sample of metal has a mass of 16.5916.59 g, and a volume of 5.815.81 mL. What is the density of this metal

Oxana [17]

Answer:

=> 2.8554 g/mL

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m) = 16.59 g

Volume (v) = 5.81 mL

From our question, we are to determine the density (rho) of the rock.

The formula:

$p = \frac{m}{v}$

Substitute the values into the formula:

$p = \frac{16.59 g}{5.81 mL} \\ = 2.8554 g/mL$

= 2.8554 g/mL

Therefore, the density (rho) of the rock is 2.8554 g/mL.

5 0

1 year ago

Which of the following are excited in ultraviolet photoelectron spectroscopy?

zavuch27 [327]

Answer:

D. Valance Electrons

Explanation:

6 0

2 years ago

1.) What coefficient values will balance the reaction shown? CH4 + O2 ?CO2 + H2O

Varvara68 [4.7K]

Answer:

It's simpler than most questions :)

Explanation:

1) B

2) B

3) D

4) A

5) A

Hope this will help :)

5 0

3 years ago

When a connector is marked with "al-cu," the connector is suitable for use with copper, copper-clad aluminum, and aluminum condu

IgorLugansk [536]

When connectors are marked with a combination of metals, it can be used as a connector of one of the metals or an alloy of the two metals. So in this case, since the marking is “Al – Cu” where Al is aluminium and Cu is copper, therefore the answer is:

Yes, it is suitable for use with copper, copper-clad aluminum, and aluminum conductors.

6 0

3 years ago

The principal source of sulfur on earth is deposits of free sulfur occurring mainly in volcanically Active regions. The offer wa

aivan3 [116]

Answer:

1.18x10⁸L of SO₂ and 2.36x10⁸L of H₂S

Explanation:

The balanced reaction is:

8SO₂(g) + 16H₂S(g) → 16H₂O(l) + 3S₈(s)

To solve this question we must find the moles of S₈ in 4.50x10⁵kg. With these moles and the reaction we can find the moles of SO₂ needed to react (Twice these moles = Moles Of H₂S needed). Using PV = nRT we can find the volume of the gas required:

Moles S₈ - molar mass: 256.52g/mol-

4.50x10⁵kg = 4.50x10⁸g * (1mol / 256.52g) =

1.75x10⁶ moles S₈

Moles SO₂:

1.75x10⁶ moles S₈ * (8mol SO₂ / 3mol S₈) = 4.68x10⁶ moles SO₂

Moles H₂S:

4.68x10⁶ moles SO₂ * 2 = 9.36x10⁶ moles H₂S

The volume could be obtained as follows:

PV = nRT

V = nRT / P

V is volume in liters

n are moles: 4.68x10⁶ moles SO₂ and 9.36x10⁶ moles H₂S

R is gas constant = 0.082atmL/molK

T is absolute temperature = 22°C + 273.15 = 295.15K

P is pressure = 0.961atm

Replacing:

Volume SO₂ and H₂S:

4.68x10⁶ moles * 0.082atmL/molK * 295.15K / 0.961atm =

9.36x10⁶ moles H₂S * 0.082atmL/molK * 295.15K / 0.961atm =

5 0

2 years ago