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nata0808 [166]
4 years ago
13

What is the total mass of KNO3 that must be dissolved in 50. grams of H2O at 60.°C to make a saturated solution?

Chemistry
2 answers:
IRINA_888 [86]4 years ago
4 0

at 60ºC:

106 g KNO₃ -------------- 100 g (H₂O)
? g KNO₃ ------------------ 50.0 g (H₂O)

mass KNO₃ = 50.0 * 106 / 100

mass KNO₃ = 5300 / 100

<span>= </span>53 g of KNO₃

answer (2)

<span>hope this helps!</span>

BARSIC [14]4 years ago
3 0

Answer:

53g

Explanation:

First we plot the solubility graph for KNO3 as shown in the image attached. From the graph, we see that the solubility of KNO3 per 100g of solution is 106g.

Hence if 106g of KNO3 dissolves in 100g

Xg of KNO3 dissolves in 50g

50×106/100 = 53g of KNO3

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Today I will explain what a valence electron is and how many valence electrons each of the atoms your asking about have. :)

→ A valence electron is an electron in the outer shell of an atom that is able to participate in bonding. While iodine has 53 electrons, all but seven are in the inner shells of the iodine atom.

→ Sulfur has sixteen electrons in total, two in the inner shell, eight in the middle, and six in the outer. This means that sulfur has six valence electrons.

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an alloy composed of tin, lead, and cadmium is analyzed. the mole ratio of sn:pb is 2.73:1.00, and the mass ratio of pb:cd is 1.
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This problem is describe the mole-ratio composition of an allow composed by tin, lead and cadmium. Ratios are given as Sn:Pb 2.73:1.00 and Pb:Cd is 1.78:1.00, and we are asked to calculate the mass percent compositon of Pb in the allow.

In this case, according to the given information, it turns out possible realize that the following number of moles are present in the alloy, according to the aforementioned ratios:

2.73mol Sn\\\\1.00molPb\\\\\frac{1.00molPb*1.00molCd}{1.78molPb}= 0.562molCd

Next, we calculate the masses by using each metal's atomic mass:

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Thus, the mass percent composition of each metal is shown below:

\%Sn=\frac{324.05g}{324.05g+207.2g+63.2g} *100\%=54.5\%\\\\\%Pb=\frac{207.2g}{324.05g+207.2g+63.2g} *100\%=34.9\%\\\\\%Cd=\frac{63.2}{324.05g+207.2g+63.2g} *100\%=10.6\%

So that of lead is 34.9 %.

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Answer:

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so V=0.05/0.2 = 0.25l = 250ml

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