Exterior angle sum of an polygon (shape) is 360 degrees (this is a property)
x + 98 + 41 + 76 + 86 = 360
Therefore x = 59
Please double check the equation I have written. Your picture is a bit blurry therefore I can really tell what number is 6 and 8. Sorry
Answer: SECOND OPTION
Step-by-step explanation:
You can solve the system of equations by the method of substitution:
- You must susbtitute the second equation into the first equation and solve or x:
- Now, you must susbtitute the value of x obtained above into the second equation to calculate the value of y. Then, you have:
Therefore, you obtain:
(
)
The answer is :
b = t - 5 / 4
y = 9ln(x)
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2
curvature k = |y''| / (1 + (y')^2)^(3/2)
<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).
To maximize the curvature, </span>
we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)
Setting k' = 0 yields x = ±9/√2.
Since k' < 0 for x < -9/√2 and k' > 0 for x >
-9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.
Since k' > 0 for x < 9/√2 (and greater than 9/√2) and
k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2. </span>
x=9/√2=6.36
<span>y=9 ln(x)=9ln(6.36)=16.66</span>
the
answer is
(x,y)=(6.36,16.66)
Answer: 10
2AX=BD
2(3y-5)=5y
6y-10=5y
add 10 to each side 6y+10-10=5y+10
6y=5y+10
subtract 5y from each side 6y-5y=5y-5y+10
6y-5y=y
y=10
