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Lapatulllka [165]
3 years ago
9

Is (-3,2) a solution of 7x+9y>-3?

Mathematics
1 answer:
AVprozaik [17]3 years ago
4 0
7(-3)+9(2)>-3
-21+18>-3
-3>-3

No
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Which number line represents the solution set for the inequality 4(x + 3) 5 2 2X?
tatuchka [14]

Answer:

-2

Step-by-step explanation:

6 0
3 years ago
Find the Domain and Range of the following: (6.-1) (-2.2) (18,-1) (-2,3) Domain: Range: Is this relation a function?​
zheka24 [161]

Answer:

Domain: {-2,6,18}

Range: {-1,2,3}

This relation is not a function.

Step-by-step explanation:

The domain is all of the x values given listed in order from least to greatest and not repeating any numbers. The range is the same thing, but with the y values given. This is not a function because multiple ordered pairs have more than one output for the input. Let's take -2 in these ordered pairs. It has two different outputs, 3 and 2. Because of this, it is not a function.

Hope this helps!!

8 0
2 years ago
Please need help I will be MARKING as BRIANILIST. thank you so much. ​
Marina86 [1]

Answer:

a. (3,11) (4,15) (5,19) (6,23)

b. it's not proportional because b (from y=mx+b) is not 0

c. the equation is y = 4x - 1

d. graph the y-int (-1) on the y-intercept and then connect the points in a.

Step-by-step explanation:

5 0
4 years ago
A music service chargers a $2.99 monthly membership fee plus $0.05 for each song purchased. If Naomi charges for the month was $
8_murik_8 [283]

Answer:

158

Step-by-step explanation:

10.89-2.99 = 7.90

.5/7.90=158

3 0
3 years ago
Read 2 more answers
Which of the following are solutions to the equation below?
Natasha2012 [34]
Both A and C would be solutions to the equation.

In order to solve for this you must first get the equation equal to 0. 

2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/- \sqrt{b^{2} - 4ac } }{2a}

\frac{-5 +/- \sqrt{5^{2} - 4(2)(2) } }{2(2)}

\frac{-5 +/- \sqrt{9} }{4}

\frac{-5 +/- 3 }{4}

\frac{-5 + 3 }{4} or -1/2 for the first answer

\frac{-5 - 3 }{4} or -2 for the second answer

5 0
3 years ago
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