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Ksivusya [100]
3 years ago
13

Two white powders were mixed together. A chemical reaction occurred, and a yellow powder was formed. What is the relationship be

tween the yellow powder and the white powders?
A. The yellow powder is made up of the same kinds of atoms as the white powders, but the atoms are combined into different molecules. The yellow powder is made up of the same kinds of atoms as the white powders, but the atoms are combined into different molecules.

B. The yellow powder is made up of the same kinds of molecules as the white powders, but the molecules are a different color. The yellow powder is made up of the same kinds of molecules as the white powders, but the molecules are a different color.

C. The yellow powder was released from inside the atoms of the white powders. The yellow powder was released from inside the atoms of the white powders.

D. There is no relationship between the yellow powder and white powders. There is no relationship between the yellow powder and white powders.
Chemistry
2 answers:
const2013 [10]3 years ago
4 0

The answer for the question is A

Sloan [31]3 years ago
3 0

Answer:

A

Explanation:

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Biden 2020 cmon now we take W’s not Ls
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3 years ago
Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0
3 years ago
6) Given that the density of olive oil is 0.92 g/mL, calculate the followin a. The mass of 20.0 mL of olive oil. The volume of 2
fgiga [73]

<u>We are given:</u>

Density of Olive oil = 0.92 g / mL

<u>Mass of 20 mL Olive oil:</u>

We know that the density = 0.92 grams / mL

multiplying the numerator and the denominator by 20

Density = 0.92 * 20 grams / 20 mL

Density = 18.4 grams / 20 mL

So, we have 18.5 grams in 20 mL of Olive oil

<u>Volume of 20 grams Olive oil:</u>

We need to multiply the numerator and the denominator of density by a number, that when multiplied by 0.92 will give 20

<em>let that number be x:</em>

<em>0.92 * x = 20</em>

<em>x = 20/0.92</em>

<em>x = 21.74 (approx)</em>

<em />

Multiplying the numerator and the denominator by x:

Density = 0.92 grams / 1 mL

Density = 0.092 * 21.74 / 21.74 mL

Density = 20 grams / 21.74 mL

So, we can see that 20 grams of the oil will have the volume 21.74 mL

4 0
3 years ago
Thats wrong because i was taking a test and that was wrong its b
djyliett [7]
What do you mean do you need hekp?

6 0
4 years ago
Calculate the concentration of a solution that has 6.7 moles in a volume of 0.6 liters.
Yuri [45]

Answer:

11.2 M

Explanation:

Given data:

Number of moles = 6.7 mol

Volume of solution = 0.6 L

Concentration /Molarity = ?

Solution:

Molarity:

It is number of moles of solute in to per kg or litters of solution. It can be calculated by the following formula.

Molarity = number of moles / Volume in L

Now we will put the values in formula.

Molarity = 6.7 mol / 0.6 L

Molarity = 11.2 mol/L

Molarity = 11.2 M

6 0
4 years ago
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