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Elena L [17]
3 years ago
15

This isn't a specific topic I need to know for school or something, Im just curious. I know the first three variable letters mos

t commonly used are x, y, and z. But what if you have more variables, what would be the next letters to use? I have seen some places saying x, y, z, and t; others x, y, z, w, p, and r; and others p, q, r, s, x, y, and z but none seemed to have a definite answer and I don't know what to use.
Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0
Hey :)

You basically can use any letters for variables, a-z, it’s totally up to you

Yes, it is very common to see x, y and z, but it is just a preference

If the question requires you to put in a variable, then just pick any letter

Hope this helps!
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Alla [95]
I can’t solve rn but take all those numbers given and add them together. then subtract that number from 132.4 and there’s your answer
4 0
3 years ago
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PLEASE HELP! Write an algebraic expression to solve this problem. A number quadrupled AGAIN is 272. What is the number? Show you
garri49 [273]
4(N)=272

Divide by 4 on both sides

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5x + 2y = 8
stich3 [128]
The answer should be c.
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3 years ago
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What is the value of C in the matrix equation below?
lara [203]

Given:

The matrix equation is:

\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}

To find:

The value of matrix C.

Solution:

Let A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}. Then the given equation can be rewritten as

A-C=B

-C=B-A

C=-(B-A)

C=A-B

On substituting the values of the matrices, we get

C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}

C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}

C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}

C=\begin{bmatrix}-4&2&-7\end{bmatrix}

Therefore, the correct option is C.

6 0
3 years ago
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15 ‒ 5x = 6x + 3 – 2x
LenKa [72]

Answer:

x = 4/3

Step-by-step explanation:

15 - 5x = 6x + 3 - 2x

In this kind of equation, we try to seperate the x's and the numbers.

So we add 5x to both sides and subtract 3 from both sides to seperate these values

15 - 3 - 5x + 5x = 6x + 3 - 3 - 2x + 5x

=> 12 = 9x

=> 12/9 = x

=> 4/3 = x

=> x = 4/3

To check, we can plug this in.

15 - 5(4/3) = 6(4/3) + 3 - 2(4/3)

15 - 20/3 = 24/3 + 3 - 8/3

45/3 - 20/3 = 24/3 + 9/3 - 8/3

25/3 = 25/3

So our answer works.

7 0
3 years ago
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