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2 years ago

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Joshua uses his thermometer and finds the boiling point of ethyl alcohol to be 75o C. He looks in a reference book and finds tha

t the actual boiling point of ethyl alcohol is 80oC. What is his percent error?

2 answers:

Crazy boy [7]2 years ago

5 0

Answer:

the percent error is 6.25%

Step-by-step explanation:

The computation of the percent error is shown below:

Percent error is

= (Experimental value - accepted value) ÷ (experimental value) × 100

= (80 degrees - 75 degrees) ÷ (80 degrees) × 100

= (5 degrees) ÷ (80 degrees) × 100

= 0.0625 × 100

= 6.25%

hence, the percent error is 6.25%

We simply applied the above formula so that the correct value could come

And, the same is to be considered

Mekhanik [1.2K]2 years ago

5 0

Answer:

6.25

Step-by-step explanation:

I just did this

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2 years ago

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Ahmad wants to practice free-throws. He estimates the distance from the free-throw Line to the hoop and marks it with chalk. Ahm

const2013 [10]

Answer: 10%

Step-by-step explanation:

The difference between his estimated and actual distance is 15 - 13.5 = 1.5

The percentage of error is the difference divided by the actual value.

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3 years ago

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X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

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Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

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2 years ago

Given that j || k, what is the measure of the missing angle?

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Its c.
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3 years ago

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Which point is part of the solution of the inequality y<=|x+4|-3

Whitepunk [10]

<h2>Hello!</h2>

The answer is: The point (0,0) is part of the solution.

<h2>Why?</h2>

To find which point is part of the solution of the inequality, we need to evaluate each of the given points. If the inequality is satisfied, then the point is part of the solution, otherwise, if the inequality is not satisfied, the point is not part of the solution.

We are given the inequality:

$y\leq |x+4|-3$

So, evaluating we have:

- First point (-2,1)

$y\leq |x+4|-3\\\\1\leq |-2+4|-3\\\\1\leq |2|-3\\\\1\leq 2-3\\\\1\leq -1$

Now, since 1 is not less or equal to -1, the point (-2,1) is not part of the solution.

- Second point (1,3)

$y\leq |x+4|-3\\\\3\leq |1+4|-3\\\\3\leq |5|-3\\\\3\leq 5-3\\\\3\leq 2$

Now, since 3 is not less or equal to 2, the point (1,3) is not part of the solution.

- Third point (-4,2)

$y\leq |x+4|-3\\\\2\leq |-4+4|-3\\\\2\leq |0|-3\\\\2\leq 0-3\\\\2\leq -3$

Now, since 2 is not less or equal to -3, the point (-4,2) is not part of the solution.

- Fourth point (0,0)

$y\leq |x+4|-3\\\\0\leq |0+4|-3\\\\0\leq |4|-3\\\\0\leq 4-3\\\\0\leq 1$

Now, since 0 is less than 1, the point (0,0) is part of the solution.

Hence, we have that the point (0,0) is part of the solution.

Have a nice day!

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2 years ago