3 years ago

Hi can you solve this problem for me 6 6x + 2y = 34 2x - 7y = -27

Mathematics

1 answer:

LiRa [457]3 years ago

7 0

Answer:

1. y−intercept= 17/-1 =−17.00000

1. x−intercept= 17/3 =5.66667

2. x−intercept= −27/2 =−13.50000

2. y−intercept= 27/7 =3.85714

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Find the exact value of sin-1 the quantity square root of three divided by two

kykrilka [37]

Answer:

Answer is 60 degrees.

Step-by-step explanation:

We know that in a right angled triangle if one leg is 1, and hypotenuse is 2,

then other leg = $\sqrt{2^2-1^2 } =\sqrt{3}$

(By using Pythagorean theotrem)

Now consider a right angle triangle with hypotenuse 2 and one leg 1, and the angle between other leg and hypotenuse.

Since sin 30 = 1/2 we have cos 60= sin (90-60) = 1/2

Hence sin 60 = rt 3 /2

Using the above we get sin inverse of quantity square root of three divided by two is 60 degrees.

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4 years ago

The sum of two numbers is 27. Their difference is 1. Find the smaller number.<br>

hjlf

Answer:

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3 years ago

Which expression is equivalent to 15 x^3 z^5/ 3 x^7 z^-5

qwelly [4]

Answer:

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3 years ago

Please help me!!!! I would really appreciate it!!!

Tpy6a [65]

Answer:

x=-(7 $\pm i\sqrt(7)$ )

Step-by-step explanation:

3 0

2 years ago

Consider this sequence

pochemuha

Hello,

$u_{1} =1*(8-7)=1*(2*4-(6+1))\\
 u_{2} =2*(10-7)=2*(2*5-(6+2))=2*(2*(4+1)-(6+2))\\
 u_{3} =3*(12-9)=3*(2*6-(6+3))=3*(2*(4+2)-(6+3))\\
 u_{4} =4*(14-10)=4*(2*7-(6+4))=4*(2*(4+3)-(6+4))\\

$

$u_{10}=10*(2*(4+10)-(6+10))\\
=10*(28-16)
$

$...\\\\
u_{n} =n*(2*(n+n-1)-(6+n))\\
=n*(4n-2-6-n)=n(3n-8)\\

$

5 0

3 years ago