-- The first urn has 9 balls in it all together, and 2 of them are white.
If you don't peek, then the prob of pulling out a white ball is 2/9 .
-- The second urn has 13 balls in it all together, and 3 of them are white.
If you don't peek, then the prob of pulling out a white ball is 3/13 .
-- The probability of being successful BOTH times is
(2/9) x (3/13) = ( 6/117 ) = about 0.0513 or 5.13% (rounded)
Answer:
64.96
Step-by-step explanation:
The most common benchmark percents are 
and 
We are given 
which is closest to 
.
Now we calculate 
which is equal to 
.
We are left with 
more to add.
We can say 
Therefore 
Now add the two.
Thus 64.96 is the answer.
First you need to get x on one side of the equation and to do that subtract 2a from both sides.
28 + 2a = 5a + 7
-2a -2a
28=3a+7
Then we need to get a alone by subtracting 7 on both sides.
28=3a+7
-7 -7
21=3a
Finally divide each side by 3 and you should get a = 7. Hope this helps!
Answer:
P(A∪B) = 1/3
Step-by-step explanation:
Red Garments = 1 red shirt + 1 red hat + 1 red pairs of pants
Total Red Garments = 3
Green Garments = 1 green shirt + 1 green scarf + 1 green pairs of pants
Total Green Garments = 3
The total number of garments = Total Red Garments + Total Green Garments:
3 + 3 = 6
Let A be the event that he selects a green garment
P(A) = Number of required outcomes/Total number of possible outcomes
P(A) = 3/6
Let B be the event that he chooses a scarf
P(B) = 1/6
The objective here is to determine P(A or B) = P(A∪B)
Using the probability set notation theory:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∩B) = Probability that a green pair of pant is chosen = P(A) - P(B)
= 3/6-1/6
= 2/6
P(A∪B) = 1/2 + 1/6 - 2/6
P(A∪B) = 2/6
P(A∪B) = 1/3
I really dont know how to explain it but its (-2,-2)
