Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Answer:
$126,000
Step-by-step explanation:
16% of 150,000 is 24,000
150,000-24,000=126,000
Answer:
hi, hope you are good!, hope you have the greatst holidays ever!
Step-by-step explanation:
Answer:
answer is of left to right
16x^14/(36x^2)=4x^12/9
(3^3)×(x^5)×y÷4
-9a^3(b^5)
Answer:
3(n + 2) > 0
Step-by-step explanation:
Work on a piece at a time.
"sum of a number and two": n + 2
"three times the sum of a number and two": 3(n + 2)
"three times the sum of a number and two is greater than zero": 3(n + 2) > 0
Answer: 3(n + 2) > 0
