Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
Answer:
25
Step-by-step explanation:
20 books in 4 months is 5 books in 1 month.
20÷4=5
4÷4=1
1×5=5
5×5=25
Answer:
F' = (7, 6)
R' = (-1, 7)
I' = (-2, -5)
O' = (6, -6)
Step-by-step explanation:
The rule of reflection over the y-axis is, (x, y) ---> (-x, y). So change all the x values into the opposite signs. So the -7 of F would turn into just 7, the 1 of R would turn into -1, the 2 of I would turn into -2, and -6 of O would turn into just 6.
Answer:
y = -1 x = 4
Step-by-step explanation:
(X+3y=1) 5 Multiply this equation by 5 to cancel out the x
-5x+4y=-24
-5x + 4y= -24
+ 5x + 15y = 5 Add both equations together
19y = -19 Divide both sides by 19
y = -1
Plug -1 for y into one of the equations
x + 3(-1) = 1 Multiply 3(-1)
x - 3 = 1
+ 3 + 3 Add 3 to both sides
x = 4
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