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3 years ago

Find the area of the circle.leave your answer in terms of

Mathematics

1 answer:

Yakvenalex [24]3 years ago

5 0

Area is 3.6*3.6*pi
Area is 12.96 pi

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PLEASE HELP WITH THIS! ITS ALREADY LATE AND I JUST WANNA GET IT DONE

MArishka [77]

The answer is 61.92 all u do is 3 x 20.64

6 0

3 years ago

If H is in the interior of ∠EFG, m∠EFH = 75°, and m∠HFG = (10x)°, and m∠EFG = (20x − 5)°, then x = ? and m∠HFG = ?

Diano4ka-milaya [45]

Answer:

$x=8$

$\m\angle HFG= 80^\circ$

Step-by-step explanation:

Given that:

Point $H$ is interior of $\angle EFG$ .

$m\angle EFH = 75^\circ\\m\angle HFG = (10x)^\circ\\m\angle EFG = (20x-5)^\circ$

To find:

$x = ?\\m\angle HFG = ?$

Solution:

First of all, let us represent the given values in the form of a diagram.

Kindly refer to the attached image for the given points and values of angles.

We can clearly see that:

$m\angle EFG = m\angle EFH + m\angle HFG$

Putting all the values given in above equation, we get:

$(20x-5)^\circ = 75^\circ + 10x^\circ\\\Rightarrow 20x-10x=75+5\\\Rightarrow 10x =80\\\Rightarrow \bold{x =8}$

$m\angle HFG =10x^\circ\\\Rightarrow m\angle HFG =10\times 8^\circ\\\Rightarrow m\angle HFG = \bold{80^\circ}$

8 0

3 years ago

How many ounces make one third of a cup

podryga [215]

2 2/3 ounces

1 cup = 8 oz
1/3 cup = 2.66667 oz

6 0

3 years ago

Read 2 more answers

In the figure, BD¯¯¯¯¯ bisects ∠ABC .

pashok25 [27]

The bisector BD is perpendicular to the line segment AC then the angle formed in between is 90°. We can solve for DC using SOH CAH TOA theorem or Pythagorean theorem.
Since ∠BDA is 90°, we can examine that AD is equal to 2units. Proving this, we have BD^2=BD^2+AD^2.
3^2=DB^2+2^2
DB=5units
Therefore, DC=AC-AD and the answer is 2 units.

5 0

3 years ago

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AD=40 and AC=48, what is the length of AB in simplest radic

Natalka [10]

Answer:

8 $\sqrt{30}$

Step-by-step explanation:

AB^2 = AD * AC

we got the answer

8 0

2 years ago