Answer:
or 
Step-by-step explanation:

The opposite of
is 

Convert decimal number −0.75 to fraction
.
Reduce the fraction
to lowest terms by extracting and canceling out 25.

Least common multiple of 4 and 5 is 20. Convert
and
to fractions with denominator 20.

Since
and
have the same denominator, add them by adding their numerators.

Add -15 and 8 to get -7

Convert decimal number 0.4 to fraction
. Reduce the fraction
to lowest terms by extracting and canceling out 2.

Least common multiple of 20 and 5 is 20. Convert
and
to fractions with denominator 20.

Since
and
have the same denominator, add them by adding their numerators.

Add -7 and 8 to get 1.

Least common multiple of 20 and 4 is 20. Convert
and
to fractions with denominator 20.

Since
and
have the same denominator, subtract them by subtracting their numerators.

Subtract 15 from 1 to get -14.

Reduce the fraction
to lowest terms by extracting and canceling out 2.
or 
Hope this helps! Brainliest would be much appreciated! Have a great day! :)
(2x-y = -3 × y = 0 × (0, 0) × ( -1, 1) × (1, -1) =
(2x - y = -3 × y =0 × (0)) ×, × 0 ×, × 1 ×, × -1
Standard form is y=mx+b
y=9x+4
Answer:
Step-by-step explanation:
perp. -4/3
y + 2 = -4/3(x - 3)
y + 2 = -4/3x + 4
y = -4/3x + 2
The amount of balloons in the tent is 125.075 feet cube. From the given options, approximately, option D is correct
<u>Solution:</u>
Given, Rob is making a tent out of canvas in the shape of a square pyramid. Each side of the square base is 6 feet long, and the height is 6.3 feet.
Rob filled the tent with balloons,
We have to find which measurement BEST describes the amount of balloons in the tent?
As tent if filled with balloons the amount of balloons equals with volume of tent.
<em><u>Volume of tent is given as:</u></em>

where "a" is side length and "h" is height.

Hence, from the given options, approximately, option D is correct.