Tammy's sample may not be considered valid because, on the first hand, it is said that she only asked students from her " Math Class".
If she wants to have a survey to find out the favorite subject of the students at her school, she must conduct a survey involving all the students in her school, not just in her class. What she did is just subjective. She should use a tally listing the different subjects and compare the number of students per subject. This way, she can have an objective representation of the least liked subjects and the most liked subjects of the students on her school.
Illustrating her survey through statistics may be more reliable and valid because it shows frequencies in which she can calculate easily and accurately the percentage of the number of students per subject, in a more objective manner.
2.50-2.00=0.5
2.50/0.5= 5 = 100%
2.00/0.5=4 = 80%
100-80= 20%
2x^2 + 8x - 12 = 0..divide by 2
x^2 + 4x - 6 = 0
x^2 + 4x = 6...add 4 to both sides of the equation
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10....<== ur constant is 10
x + 2 = (+-)sqrt 10
x = -2 (+ - ) sqrt 10
x = -2 + sqrt 10
x = -2 - sqrt 10
The charity will receive $ 11
<h3><u>
Solution:</u></h3>
Ken earned $176 from his part-time job this summer
Amount earned = $ 176
He spent 25% of his money on games
Therefore,
Money spent on games = 176 - 25 % of 176
He is going to donate 1/4 of the remaining money to charity
Reamining amount = 176 - 132 = 44
Therefore,
Thus he gave $ 11 to charity
Answer:
90°.
Step-by-step explanation:
if AR is diameter and the angle ∠AOR (it's m∠2) is based on this diameter, then its measure is 90°. It is central angle.
