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Burka [1]
1 year ago
7

Mr. Chung drove 248 miles in 4 hours. If he continues driving at the same speed, how many miles will Mr.Chung drive in 6 hours?​

Mathematics
1 answer:
marusya05 [52]1 year ago
6 0

Answer:

Step-by-step explanation:

248miles ÷ 4hrs = 62mph

62mph × 6 hrs = 372miles

Mr. Chung will have driven <u>372 miles</u> in 6 hours

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Which expression has a value of 22? A. 14 + 2 x 5. B. (14+2) x 5 C. 24 - 6÷ 3. D. (24 - 6) ÷ 3
zimovet [89]

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

A. 14 + 2 × 5 = 14 + 10 = 24 ≠ 22

B. (14 + 2) × 5 = 16 × 5 = 80 ≠ 22

C. 24 - 6 ÷ 3 = 24 - 2 = 22

D. (24 - 6) ÷ 3 = 18 ÷ 3 = 6 ≠ 22

<h3>Answer: C.</h3>
5 0
3 years ago
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The Opera House sells an average of 1,700 tickets per night when the price of each ticket is $25. An employee of the Opera House
irakobra [83]
So here's the solution to the problem:

Calculate the average sell:

1,700 * $25 = $42,500 (revenue)

And if the Opera House wants to increase their revenue:

The price of a ticket will be:

$25 - x (where x is the number of 1-dollar decreases)

The number of tickets in total:

1,700 + 200x

Therefore the equation is:

(1,700 +200x) * ( 25 - x ) = 55,000

We can also solve this equation, but the solutions are not whole numbers.

x 1 = 5.89 and x 2 =10.6

For x = 6 (6 times 1 - dollar decreases):

( 1,700 + 200 * 6 ) * ( 25 - 6 ) = ( 1,700 + 1,200 ) * 18

=2,900 *19 = 55,100 (we will yield the revenue over $55,000)
3 0
3 years ago
At the frozen yogurt shop, a machine fills cups with 4 ounces of frozen yogurt before adding the toppings. After the cups are fi
Otrada [13]
What are the options?

3 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Solve 4(-2x + 7) = 24 for x
tamaranim1 [39]

Answer:

x = 1/2

Step-by-step explanation:

brainlest please

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    4*(-2*x+7)-(24)=0

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 4 • (7 - 2x) -  24  = 0

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  4 - 8x  =   -4 • (2x - 1)

Equation at the end of step  3  :

 -4 • (2x - 1)  = 0

Step  4  :

Equations which are never true :

4.1      Solve :    -4   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2      Solve  :    2x-1 = 0

Add  1  to both sides of the equation :

                     2x = 1

Divide both sides of the equation by 2:

                    x = 1/2

6 0
3 years ago
Read 2 more answers
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