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Aleks [24]
3 years ago
15

Plz help me understand this question thankyou

Mathematics
2 answers:
Andre45 [30]3 years ago
3 0

Answer:

The mistakes were on points C and D

Step-by-step explanation:

Point C was graphed on (5,8) when it's supposed to be plotted on (5,7). Point D was on (-3,-4) but was supposed to be on (-4,-3?

inessss [21]3 years ago
3 0

Answer:

The mistakes are Point C and D

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SOMONE HELP ME I HAVE <br> TO DO THIS AFTER SCHOOL PLS ASAP!!!
Scrat [10]

Answer:

1 no

2 I don't know

3 no

4 yes

5 2.5 is the slope

6 -0.5

7 no slope

Step-by-step explanation:

1 no because the y overlaps

2 not sure

3 it over laps

4 it never overlaps

5 y=2.5x-3

6 y=-0.5x+1

7 no slope it's just x=-2

for the 5-7 you can type that into demos and get more info

y=mx+b

m is the slope and b is y intercept

3 0
2 years ago
7/6 * 16/6 in simplest form​
Slav-nsk [51]

Answer:

3.83333333333

Step-by-step explanation:

6 0
3 years ago
Solve for x: x - 9 = 15<br><br> A. 6<br> B. 24<br> C. -24<br> D. -6
Oduvanchick [21]

Answer:

X = 24

Step-by-step explanation:

Add 9 To Both Sides

X - 9 + 9 = 15 + 9

Simplify

X = 24

Best Of Luck,

- I.A. -

4 0
3 years ago
Read 2 more answers
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
I need help it’s due in 10 mins ASAP <br> I’ll mark you as a brainlist please help
Lady_Fox [76]
Take DEBC a parralelogram
Parralel sides are DE and BC
THEREFORE,
1/2*(a+b)*h
1/2*(6+15)*h
1/2*(21)*h=0
10.5*h=0
h=-10.5
3 0
3 years ago
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