Answer:
The Answer is: Josh hit 47 balls.
Step-by-step explanation:
Let j = Josh number of hits and c = Caiden number of hits:
j = c/2 + 9
Total:
j + c = 123.
Substitute:
(c/2 + 9) + c = 123
c/2 + c = 123 - 9
c/2 + c = 114
1/2c + 2/2c = 114
3/2c = 144
c = 144 (2/3) = 76, Number of hits for Caiden
Solve for j:
j = 76/2 + 9
j = 38 + 9 = 47, number of hits for Josh
Proof:
j + c = 123
47 + 76 = 123
123 = 123
Hope this helps! Have an Awesome Day!! :-)
N; n + 2 - the two consecutive even integers
n + 3(n + 2) = 46
n + 3n + 6 = 46 <em> |subtract 6 from both sides</em>
4n = 40 <em> |divide both sides by 4</em>
n = 10
n + 2 = 10 + 2 = 12
<u>Answer: 10 and 12.</u>
Answer:
Step-by-step explanation:
Multiply both sides of the equation by 99, the least common multiple of 9,39,3.
m + 6 =21
Subtract 6 from both sides.
m = 21 - 6
Subtract 6 from 21 to get 15.
m=15
If two dices are rolled once, you would have a total number of 6*6=36 possibilities.
To get a sum greater than 10:
A) one of your dices could be showing a 5, the other a 6. That’s two possibilities. Dice A being the 5 or dice B being the 5.
B) both of your dices could be showing 6s.
That’s one possibility.
So your overall possibility to get a sum greater than 10 is (1+2)/36 3/36=1/12
One twelfth.
Moooooooosssssssssseeeeeeeeseseses
