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Mice21 [21]
3 years ago
10

The area of the shaded region of the figure is _____ mm ²

Mathematics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

400mm^2

Step-by-step explanation:

You might be interested in
Write an ordered-pair rule for the translation in the sequence that maps AEFG to AE'F'G'. 4 Points ANSWER: Translation rule: (x,
Anastasy [175]

The translation rule is:

(x,y) \rightarrow (x + 4, y - 5)

  • F(1,4) is mapped to F'(5,-1), that is, 4 is added to the x-coordinate and 5 is subtracted from the y-coordinate.
  • G(2,2) is mapped to G'(6,-3), which is the same change as in F.
  • The same happens for E(-1,2), which is mapped to E'(3,-3).

Thus, the translation rule when <u>4 is added to the x-coordinate and 5 is subtracted from the y-coordinate</u> is:

(x,y) \rightarrow (x + 4, y - 5)

A similar problem is given at brainly.com/question/23960579

5 0
2 years ago
A finite set of points in the plane has the property that the triangle formed by any 3 of them has area less than 1.Prove that t
Ainat [17]

Explanation:

All of the points must be contained within a circle that will circumscribe an equilateral triangle of area 1. (We refer to this as the inscribed triangle.) Any points on the circle that do not form an equilateral triangle will form a triangle with an area less than 1. Likewise for any points within the circle.

The circle can be circumscribed by an equilateral triangle whose side length is double that of the inscribed triangle. Since the side length is double, the circumscribing triangle will have an area 2² = 4 times that of the inscribed triangle.

The inscribed triangle has an area of 1, so the circumscribing triangle must have an area of 4.

3 0
3 years ago
Answer dis please- Thanks
hodyreva [135]

Answer:

Since we know that ABCD ~ EFGH, we have the ratios:

EF/AB = GH/CD

=> 0.4/1.2 = x/1.8

=> x = (1.8 . 0.4)/1.2 = 0.6

So x = 0.6

8 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
3 years ago
4/7 - x = 6/35 what is x? how do I determine the answer?
vivado [14]
4/7 - x = 6/35

You're trying to get x by itself, so you have to subtract 4/7 from both sides.

-x = 6/35 - 4/7

You need both of the fractions to the right of the equal sign to have the same denominator so that we could simplify them, so multiply 5/5 to -4/7.

-4 /7 × 5/5 = -20/35

So, our new equation is :

-x = 6/35 - 20/35

Simplify.

-x = -14/35

Divide both sides by -1.

x = 14/35

Divide by 7.

x = 2/5

~Hope I helped!~
7 0
3 years ago
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