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MaRussiya [10]
3 years ago
7

Can you give me the anwsers fast pls

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

false true false true

Step-by-step explanation:

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Brandon mows the neighbor's yard to earn extra
olganol [36]

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7 is the answer you're looking for

5 0
3 years ago
Solve the proportion 8/3 = g/3
Furkat [3]

Answer:

g= 8

Step-by-step explanation:

7 0
3 years ago
Victoria went shopping for ingredients to make a stew. The table shows the
torisob [31]

Answer:

Step-by-step explanation:

It is hard for me to read but you take the weight times the cost per pound to find out how much

IF you buy potatoes 6.3 pounds times $7.56 a pound = $47.63 total

but IF its 6.3 pound at a total cost of $7.56 you divide to find the per pound price.  $7.56 ÷ 6.3 pounds = $1.20 a pound.

to check this you take your answer $1.20 times the number of pounds bought 6.3 = $7.56

7 0
3 years ago
Here are the first five terms of an arithmetic sequence.
Assoli18 [71]

Answer:

The nth term of an AP will be 27 -7n.

Step-by-step explanation:

First five terms of the Arthemetic Sequence is given to us , which is 26 , 19 , 12 , 5

Hence here Common Difference can be found by subtracting two consecutive terms . Here which is 19 - 26 = (-7) .

Here first term is 26 .

And the nth term of an AP is given by ,

★ T_n = a + ( n - 1) d

<u>Subst</u><u>ituting</u><u> respective</u><u> values</u><u> </u><u>,</u>

⇒ T_n = a + ( n - 1 )d

⇒ T_n = 26 + (n - 1)(-7)

⇒ T_n = 26 -7n+1

⇒ T_n = 27 - 7n

<h3><u>Hence </u><u>the</u><u> </u><u>nth</u><u> </u><u>term</u><u> of</u><u> an</u><u> </u><u>AP</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>found </u><u>using </u><u>T_</u><u>n</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u><u>-</u><u> </u><u>7</u><u>n</u><u>. </u></h3>

8 0
3 years ago
The mass (m grams) of a bar of gold is directly proportional to its volume (V cm3)
Anni [7]

Answer:

The volume of a bar of gold with a mass of 66.5 grams is  3.5cm^{3}

Step-by-step explanation:

Given ,  mass(in grams)  ∝ Volume (in cm3)

Here, volume of  95 grams bar = 5cm3

So, thevolume of 1 gram bar = \frac{5 cm^{3} }{95 g}  = \frac{1}{19}  cm^{3}

⇒The volume of  a bar with weight 66.5 grams =  \frac{1}{19}  \times 66.5 =  3.5 cm^{3}

So, the volume of a bar of gold with a mass of 66.5 grams is  3.5cm^{3}

7 0
4 years ago
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