Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

$d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}$

and we found the distance PQ and QA

; $d_{PQ}=\sqrt{125}$ , $d_{QA}=12$

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0

3 years ago

Helppppppp asappppp

vaieri [72.5K]

Answer:

Your answer is 87.487699

4 0

3 years ago

Please help me ASAP

V125BC [204]

I'd say it's "convergent and doesn't have a sum"

because it's multiplying by 3 to get every new number and switching between ± after every new number. there is no sum because it's an infinite series.

8 0

3 years ago

How can we simplify the expression -(1-5n)-7n

dsp73

$-(1-5n)-7n \\ \\ -1 + 5n - 7n \\ \\ -1 - 2n \\ \\ Answer: \fbox {-1 - 2n}$

5 0

3 years ago