It would be 6/7 if im not mistaken.
The required zero places of the given equation y= x² + 5x + 6 is x = -2 and x = -3.
Given that,
An equation y= x² + 5x + 6,
To determine the Zeros of the equation given above.
<h3>What is the equation?</h3>
The equation is the relationship between variables and is represented as y =ax + b is an example of a polynomial equation.
Here, given equation is, y= x² + 5x + 6
Now, let y = 0
x² + 5x + 6 = 0
x² + 2x + 3x + 6 = 0
x(x + 2) + 3 (x + 2) = 0
(x + 2) * (x + 3) = 0
x + 2 = 0 ; x + 3 = 0
x = -2 and x = -3
Thus, the required zero places of the given equation y= x² + 5x + 6 is x = -2 and x = -3.
Learn more about the equation here:
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Answer: (2, 3)
Step-by-step explanation: This graph depicts a parabola. The vertex of a parabola is the point at the intersection of the parabola, and it is the line of symmetry. In other words, it is the point where the parabola crosses its axis of symmetry. Therefore, the ordered pair of (2, 3) represents the vertex of this graph.
Answer:
It is a.
Step-by-step explanation:
Staring from the left we see that the line has a slope of 1 and a y intercept of (0,1). So the equation is y = x + 1. The filled circle at x = 2 shows that x = 2 is included in the domain so correct is y = x + 1 x ≤ 2.
Then this line is moved up 1 unit to give the equation y = x + 2 and the clear circle shows that this point x = 2 is not included in the domain so we have
y = x + 2 x > 2,
D, because for each element of the set of X, there is only one corresponding element of the set of Y.